Return rate, r = 3% = 0.03
x = initial investment
b = final balance
After 1 year, the balance i
b = initial investment + interest
b = x + r*x = (1 + r)*x
Because r = 0.03,
b = 1.03x (after 1 year)
There are no zeroes for an expression, only for equations.
Assuming equation to be
<span>−7x^2 − 91x − 280=0
-7(x^2+13x+40)=0
-7(x+8)(x+5)=0
by the zero product properties,
x+8=0 => x=-8
or
x+5=0 => x=-5</span>
Answer:
the answer is 200
Step-by-step explanation:
Answer:
Selena's annual intake home salary is $ 26,640.
Step-by-step explanation:
Since Selena's gross annual salary as the content editor of a fashion Magazine is $ 40,000, and she contributes 10% of her salary before she pays taxes to a retirement account, and 25% of her remaining salary is then consumed in state and federal taxes, To determine what is Selena's annual intake home salary if she also has to pay $ 30 for health Insurance each month, the following calculation must be performed:
40,000 - (40,000 x 0.1) - (40,000 x 0.9 x 0.25) - (30 x 12) = X
40,000 - 4,000 - 9,000 - 360 = X
26.640 = X
Therefore, Selena's annual intake home salary is $ 26,640.
Part A:
The average rate of change refers to a function's slope. Thus, we are going to need to use the slope formula, which is:

and
are points on the function
You can see that we are given the x-values for our interval, but we are not given the y-values, which means that we will need to find them ourselves. Remember that the y-values of functions refers to the outputs of the function, so to find the y-values simply use your given x-value in the function and observe the result:




Now, let's find the slopes for each of the sections of the function:
<u>Section A</u>

<u>Section B</u>

Part B:
In this case, we can find how many times greater the rate of change in Section B is by dividing the slopes together.

It is 25 times greater. This is because
is an exponential growth function, which grows faster and faster as the x-values get higher and higher. This is unlike a linear function which grows or declines at a constant rate.