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yKpoI14uk [10]
3 years ago
8

Julie ran 8 laps around her track that is a quaurter mile in 18 mins. her average velocity was __________m/s

Mathematics
2 answers:
Dimas [21]3 years ago
8 0
Her average velocity will be
.44 the 4will be repeated so you can put you answer as
.44or.4
disa [49]3 years ago
6 0

Answer:

0 the awnser is 0

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james brewer purchased 100 shares of stock for $73 a share. james also paid a $60 commission. what was the total purchase price
Ulleksa [173]

Based on the calculation below,  the total purchase price for this transaction is $7,360.

<h3>How do we calculate the total purchase price of shares of stock?</h3>

The total purchase price for this transaction can be calculated using the following formula:

Total purchase price = (Price per share * Units of shares purchased) + Commission ...................................... (1)

Substituting all the values into equation (1), we have:

Total purchase price = ($73 * 100) + $60 = $7,360

Learn more about share purchases here: brainly.com/question/20490753.

#SPJ11

5 0
2 years ago
Read 2 more answers
Square root of 3 times sec beta plus 2
NARA [144]
What is the nature of your question and what do u mean sec beta
6 0
3 years ago
An expression is shown below:
seraphim [82]
3(m + 5 + 9m)

A.
(1) 3m + 15 + 27m
(2) 3(10m + 5)

B. 3(m + 5 + 9m)....distributive property
     (3 * m) + (3 * 5) + (3 * 9m) =
    3m +  15 + 27m

C. 3(m + 5 + 9m) = 3(10m + 5)......m = 1
     3(1 + 5 + 9(1) = 3(10(1) + 5)
     3(1 + 5 + 9) = 3(10 + 5)
     3(15) = 3(15)
     45 = 45

7 0
3 years ago
Write an equation. Then solve the problem. Arturo built 3 sandcastles with 6 towers each. Paco built 5 sandcastles with 4 towers
vlabodo [156]
To get the answer we have to find number of towers.
If Arturo built 3 sandcastles with 6 towers each we can say that Arturo built
3*6=18 towers
If Paco built 5 sandcastles with 4 towers each we can say that Paco built
5*4=20 towers
20-18=2 - difference between Paco and Arturo
Answer:Arturo made more towers. The difference is 2.
8 0
3 years ago
To input your angle measures in degrees, use the functions sind, cosd and tand, instead of sin, cos and tan. Zach stands at the
kramer

Answer:

  about 2949 feet

Step-by-step explanation:

The geometry of the situation can be modeled by a right triangle. The height of the cliff can be taken to be the side opposite the given angle, and the distance to the coyote will be the side adjacent to the given angle. The relation between these values is the trig function ...

  Tan = Opposite/Adjacent

__

<h3>setup</h3>

Filling in the known values, we have ...

  tan(6°) = (310 ft)/(distance to coyote)

<h3>solution</h3>

Multiplying by (distance to coyote)/tan(6°) gives ...

  distance to coyote = (310 ft)/tan(6°) ≈ 310/0.105104 ft

  distance to coyote ≈ 2949.453 ft

The coyote is about 2949 feet from the base of the cliff.

6 0
2 years ago
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