Answer:
x - axis
Step-by-step explanation:
Since, y-coordinate of point (6, 0) is zero.
Hence, it lies on x - axis.
To find the slope intercept form of a line perpendicular to a given equation, the first thing you need to do is to find the slope of the perpendicular line. Because lines perpendicular to one another are always have a slope that is the negative reciprocal of them, the slope of the line perpendicular to y=x would be -1 (since the slope of y=x is 1). Then, since the perpendicular line passes through the point (5, -3), you would plug in the values of the x and y into the equation
y=-1x+b to get -3=-1(5)+b.
When you simplify, solve for b to get b=2. Now that you have your slope (m=-1) and your y-intercept (b=2), you can conclude that your perpendicular equation would be y=-x+2.
Slope = (10-1)/(1+2) = 9/3 = 3
y = mx + b
1 = 3(-2) +b
1 = -6 + b
b = 7
equation
y = 3x + 7
or
3x - y = -7
answer is <span>3x − y = −7 (first choice)</span>
Answer:
23 x + 62
Step-by-step explanation:
Simplify the following:
5 (4 x + 12) + 3 x + 2
5 (4 x + 12) = 20 x + 60:
20 x + 60 + 3 x + 2
Grouping like terms, 60 + 20 x + 3 x + 2 = (20 x + 3 x) + (60 + 2):
(20 x + 3 x) + (60 + 2)
20 x + 3 x = 23 x:
23 x + (60 + 2)
60 + 2 = 62:
Answer: 23 x + 62
Answer:
There is an infinite number of lines that pass through the point (2, 11). Therefore, there is an infinite number of equations. To define a single line, you must have at least two points. One point is not enough.
