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zloy xaker [14]
3 years ago
12

0=4t-16t^2 Solve this please

Mathematics
1 answer:
vaieri [72.5K]3 years ago
7 0

Answer:

\large\boxed{t=0\ \vee\ t=\dfrac{1}{4}}

Step-by-step explanation:

4t-16t^2=0\qquad\text{divide both sides by 4}\\\\\dfrac{4t}{4}-\dfrac{16t^2}{4}=\dfrac{0}{4}\\\\t-4t^2=0\\\\t(1-4t)=0\iff t=0\ \vee\ 1-4t=0\\\\1-4t=0\qquad\text{subtract 1 from both sides}\\\\-4t=-1\qquad\text{divide both sides by (-4)}\\\\t=\dfrac{1}{4}

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PLS HELP!! You have a dog crate that will hold up to 40 pounds. You have 2 dogs and need to transport them using a crate. One do
professor190 [17]

Answer:

Yes.

Step-by-step explanation:

22.75 + 15.2 =?

22+15= 37

.75 +.2 = .95

37+.95 = 37.95

5 0
2 years ago
Only the circled ones
ozzi
2.

M must be (0,0) since it coincides with the origin
R must be (a+b, √(a²-b²)).
The x-coordinate is b from A translated to the right by a.
The y-coordinate is the same as A.

(I think the square root is there to confuse you).

3.

R(0,0)
C(a,b) (same x as T, same Y as E)

5.

Not sure how to prove that.

5 0
3 years ago
the perimeter of the rectangle below is 98 units. Find the length of CD. Write your answer without variables. cd=4x+3 cb=5x+1
zimovet [89]

2(4x + 3) + 2(5x + 1) = 98 \\ 8x + 6 + 10x + 2 = 98 \\ 18x + 8 = 98 \\ 18x = 90 \\  x = 5
Substitute x with 5,

CD =
4x + 3 \\  = 4(5) + 3 \\  = 20 + 3 \\  = 23
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Hope this helps.
7 0
3 years ago
Read 2 more answers
Solve equation by using the quadratic formula.
Sati [7]

Answer: 1:  x=3, x=1

2:  x= -5

3:  There are 2 real solutions.

4:  There are 2 real solutions.

5:  There are no real solutions.

6.  There is 1 real solution.

7.  

8.  x= -6, x = -2

9.  x = -1/6, x=1

10.  

Explanation:

1.  The quadratic formula is

Substituting our known information we have:

2.  Rewriting the quadratic in standard form we have x²+10x-25=0. Substituting this into the quadratic formula gives us:

3.  The discriminant is b²-4ac.  For this problem, that is 20²-4(-4)(25)=400--400=800.  Since this is greater than 0, there are 2 real solutions.

4.  The discriminant in this problem is 7²-4(2)(-15)=49--120=49+120=169.  This is greater than 0, so there are 2 real solutions.

5.  The discriminant in this problem is 1²-4(-2)(-28)=1-224=-223.  Since this is less than 0, there are no real solutions.

6.  If the discriminant of a quadratic is 0, then by definition there is 1 real solution.

7.  Rewriting the quadratic we have 3x²-4x-2=0.  Using the quadratic formula we have:

8.  Factoring this trinomial we want factors of 12 that sum to 8.  6*2 = 12 and 6+2=8, so those are our factors.  This gives us:

(x+6)(x+2)=0

Using the zero product property we know that either x+6=0 or x+2=0.  Solving these equations we get x= -6 or x= -2.

9.  Factoring this trinomial we want factors of 6(-1)=-6 that sum to -5.  (-6)(1)=-6 and -6+1=-5, so this is how we "split up" the x term:

6x²-6x+1x-1=0

We group together the first two and the last two terms:

(6x²-6x)+(1x-1)=0

Factor the GCF out of each group.  In the first group, that is 6x:

6x(x-1)+(1x-1)=0

In the second group, the GCF is 1:

6x(x-1)+1(x-1)=0

Both terms have a factor of (x-1), so we can factor it out:

(x-1)(6x+1)=0

Using the zero product property, we know either x-1=0 or 6x+1=0.  Solving these equations we get x=1 or x=-1/6.

10.  Substituting our information into the quadratic formula we get:

Step-by-step explanation:

5 0
2 years ago
NO NEED FOR EXPLANATION
lorasvet [3.4K]
Answer:

I think is 2
7 0
3 years ago
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