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3 years ago

A.

Mathematics

1 answer:

victus00 [196]3 years ago

4 0

Answer:

I think interest earned ❤️

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Your cell phone plan costs $39.99 per month plus $0.14 for each text message you send or receive. You have at most $43 to spe

ololo11 [35]

No more than 33 texts a month
you know the total amount spent, you know the total of the bill without texts
45=39.99+.15t

6 0

3 years ago

Which angle measures are correct ? Check all that apply .

Aneli [31]

Correct
m<2 = 125
m<8 = 55
m<14 = 100
m<16 = 80

8 0

3 years ago

I need help please please

miv72 [106K]

Answer:

The value of x is 7.

Step-by-step explanation:

First, you have to make the left side into 1 fraction by making the denormintor the same and make it into simplest form :

$\frac{x}{3} + \frac{x}{6}$

$= \frac{x \times 2}{3 \times 2} + \frac{x}{6}$

$= \frac{2x}{6} + \frac{x}{6}$

$= \frac{2x + x}{6}$

$= \frac{3x}{6}$

$= \frac{x}{2}$

Next you have to multiply both sides by 2 in order to make x the subject :

$\frac{x}{2} = \frac{7}{2}$

$\frac{x}{2} \times 2 = \frac{7}{2} \times 2$

$x = 7$

5 0

3 years ago

The lengths of lumber a machine cuts are normally distributed with a mean of 106 inches and a standard deviation of 0.3 inch. (

Vinvika [58]

Answer:

a) $P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

b) $z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

Step-by-step explanation:

Let X the random variable that represent the lengths of a population, and for this case we know the distribution for X is given by:

$X \sim N(106,0.3)$

Where $\mu=106$ and $\sigma=0.3$

Part a

We are interested on this probability

$P(X>106.11)$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

And using this formula we got:

$P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

Part b

For this case we select a sample of n =44 and the new z score formula is given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score we got:

$z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

6 0

3 years ago

If you had to add two fractions with denominators of 4 and 5. What might the denominator of the sum be? Show more than one possi

mylen [45]

Answer:

your answer would be 20 because you would find what both can go into.

5 0

3 years ago