How to figure the diameter if you know circumference , the circumference is 10

A farmer sells 8.3 kg of apples and pears at the farmers market this way is apples and Restless Paris how many kilograms of Pari

Serga [27]

Answer:

She sell 2.075 kilograms of pears at the farmer's market.

Step-by-step explanation:

There is a mistake in the question some data is missing, so the correct question is below:

A farmer sells 8.3 kg of apples and pears at the farmer's market. 3 /4 of this weight is apples, and the rest is pears. How many kilograms of pears did she sell at the farmer's market?

Now, to find the kilograms of pears.

Total weight of apples and pears = 8.3 kg.

Weight of apples = $\frac{3}{4}$ of 8.3 kg.

So, to get the weight of apples:

$\frac{3}{4} \times 8.3$

$=0.75\times 8.3$

$=6.225\ kg.$

Thus, the weight of apples = 6.225 kg.

Now, to get the weight of pears we subtract the weight of apples from the total weight of apples and pears:

$8.3-6.225\\\\=2.075\ kg.$

Therefore, she sell 2.075 kilograms of pears at the farmer's market.

5 0

4 years ago

(I WILL GIVE BRAINLIEST) PLEASE HELP!

vfiekz [6]

Answer: im pretty sure its c

Step-by-step explanation: the numbers start at negative and show it is less then until it is it at the highest positive number

8 0

3 years ago

Read 2 more answers

A figure is dilated by a scale factor of 3. If the origin is the center of dilation, what is the image of a vertex located at (3

Elenna [48]

Answer:

a

Step-by-step explanation:

5 0

3 years ago

Mr. Green teaches mathematics and his class recently finished a unit on statistics. The student scores on this unit are: 40 47 5

Harrizon [31]

Answer:

Mean = 64.46, Median = 62 and Mode = Bi-modal (50 and 62)

Range of the data is 55.

Step-by-step explanation:

We are given that Mr. Green teaches mathematics and his class recently finished a unit on statistics.

The student scores on this unit are: 40, 47, 50, 50, 50, 54, 56, 56, 60, 60, 62, 62, 62, 63, 65, 70, 70, 72, 76, 77, 80, 85, 85, 95.

We know that Measures of Central Tendency are: Mean, Median and Mode.

Mean is calculated as;

Mean = $\frac{\sum X}{n}$

where $\sum X$ = Sum of all values in the data

n = Number of observations = 24

So, Mean = $\frac{40+ 47+ 50+ 50+ 50+ 54+ 56+ 56+ 60 +60+ 62+ 62+ 62+ 63+ 65+ 70+ 70+ 72+ 76+ 77+ 80+ 85+ 85+ 95}{24}$

= $\frac{1547}{24}$ = 64.46

So, mean of data si 64.46.

For calculating Median, we have to observe that the number of observations (n) is even or odd, i.e.;

If n is odd, then the formula for calculating median is given by;

Median = $(\frac{n+1}{2})^{th} \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.} }{2}$

Now here in our data, the number of observations is even, i.e. n = 24.

So, Median = $\frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.} }{2}$

= $\frac{(\frac{24}{2})^{th}\text{ obs.} +(\frac{24}{2}+1)^{th}\text{ obs.} }{2}$

= $\frac{(12)^{th}\text{ obs.} +(13)^{th}\text{ obs.} }{2}$

= $\frac{62 + 62 }{2}$ = $\frac{124}{2}$ = 62

Hence, the median of the data is 62.

A Mode is a value that appears maximum number of times in our data.

In our data, there are two values which appear maximum number of times, i.e. 50 and 62 as these both appear maximum 3 times in the data.

This means our data is Bi-modal with 50 and 62.

The Range is calculated as the difference between the highest and lowest value in the data.

Range = Highest value - Lowest value

= 95 - 40 = 55

Hence, range of the data is 55.

5 0

4 years ago

Given the following relations on the set of all integers where (x,y)∈R if and only if the following is satisfied. (Check ALL cor

Wewaii [24]

Answer:

a) symmetric

b) symmetric, reflexive, transitive

c) antisymmetric

d) symmetric

Step-by-step explanation:

(a) x+y = 0

- this relation is not reflexive, because the only element that relates with itself is 0. x+x = 2x, x+x = 0 only if 2x = 0, hence x = 0. Since 0 relates with itself, then the relation isnt irreflexive either.

Note that for x,y such that x R y, we have that x+y = 0, therefore, y = -x.

-If x,y,z are such that x R y, y R z, then y = -x, z = -y = -(-x) = x. In general x does not relate with z because z=x and the relation isnt reflexive, thus the relation is not transitive. For example, if x = z = 2, y = -2, we have that xRy, yRz, but x does not relate with z.

- This realtion is symmetric due to the commutativity of the sum. If xRy, then x+y = 0, and y+x = x+y = 0, hence yRx. Therefore, the relation cant be antisymmetric, because every element different from 0 relates to its opposite. For example 2R-2, -2R2 but 2 ≠ -2.

b) x-y is an integer

Since we are taking the substraction of two integers, the result will always be integer. Hence, every pair of elements relate within each other. As a result, the relation is symmetric, reflexive and transitive. However, it is not irreflexive nor antisymmetric, because for example 4R4, and 4R8, 8R4, but 4 is not 8.

c) x = 2y

Note that x = 2x only if x = 0, so the relation is neither reflexive nor irreflexive.

The relation is not symmetric, for example, 4R2 because 4 = 2*2, but 2 does not relate with 4, because 4*2 = 8. However, the relation is antisymmetric, because if xRy, yR2, we have

x = 2y

y = 2x = 2(2y) = 4y

since y = 4y, y should be 0, and x = 2*0 = 0. Therefore x=y = 0. The relation is antisymmetric.

The relation isnt transitive: 2R4, 4R8, but 2 does not relate with 8 because 8*2 = 16.

d) xy>1

since 0² = 0, 0 does not relate with itself, hence the relation is not reflexive. It is not irreflexive either, because, for example, 2*2 = 4 > 2, thus 2 relates with itself.

The relation is not transitive: 1 relates with every integer greater than itself, but it does not relate with itself, for example 1R7 and 7R1 because 1*7=7*1 = 7 > 1, but 1*1 = 1, it is not greater than 1, hence 1 doesnt relate with itself. This also shows that the relation is not antisymmetric either, because 1R7, 7R1 but 1≠7. The relation, however, is symmetric due to the commutativity of the product. If xy > 1, then yx = xy >1 as well.

I hope that works for you!

8 0

4 years ago