All categories

3 years ago

1 1/5+3 2/5 as a fraction

Mathematics

2 answers:

mr_godi [17]3 years ago

8 0

Answer:

23/5
4 3/5

Step-by-step explanation:

1 1/5 + 3 2/5
=> 6/5 + 17/5
=> 23/5

Conclusion:

Therefore, the answer is:

23/5
4 3/5

Hoped this helped.

$GeniusUser$

Andrej [43]3 years ago

7 0

Answer:

23/5

-------------------------

You might be interested in

-4 1/2 + (-2 1/3) <img src="https://tex.z-dn.net/?f=-4%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2B%20%28-2%20%5Cfrac%7B1%7D%7B3%7D%20

sveta [45]

$-4\frac12+(-2\frac13)=-4\frac12-2\frac13=-4\frac36-2\frac26=-(4\frac36+2\frac26)=-6\frac56\\\\\\5\frac25-6\frac57=5\frac{2\cdot7}{5\cdot7}-6\frac{5\cdot5}{7\cdot5}=5\frac{14}{35}-6\frac{25}{35}=-(6\frac{25}{35}-5\frac{14}{35})=-1\frac{11}{35}$

3 0

3 years ago

What is the height of the cylinder given v=904.78 cm^3 and r =6 cm ^2

antiseptic1488 [7]

V = (pi)r^2 * h
V / (pi)r^2 = h
V = 904.78
r = 6

904.78 / (3.14 * 6^2) = h
904.78 / (3.14 * 36) = h
904.78 / 113.04 = h
8.004 rounds to 8 = h........height is 8 cm

7 0

3 years ago

A flush is when you have 5 cards of the same suit. (There are four suits -- clubs, diamonds, hearts, and spades in a standard de

OleMash [197]

1st card = 13/52
2nd card = 12/51
3rd card = 11/50
4th card = 10/49
5th card = 9/48

13/52 * 12/51 * 11/50 * 10/49 * 9/48 = 33/66640

there are 4 different suits so 4 * 33/66640 = 33/16660
answer is C

4 0

4 years ago

Read 2 more answers

Suppose that there are 20 numbers in a data set and that they are all different. How many of the values in this data set are bet

antoniya [11.8K]

Answer:

10 Values

Step-by-step explanation:

We would use a set of data for illustration

Given the set of numbers:

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20

Since we have an even number of data, the median is in between 10 and 11.

(1,2,3,4,5,6,7,8,9,10),(11,12,13,14,15,16,17,18,19,20)

Lower Half: (1,2,3,4,5,6,7,8,9,10)

The median of the lower half is in between 5 and 6. So $Q_1$ is in between 5 and 6.

Upper Half:(11,12,13,14,15,16,17,18,19,20)

The median of the upper half is in between 15 and 16. So $Q_3$ is in between 15 and 16.

Therefore, we have the [position of the first and third quartiles as:

1,2,3,4,5, $Q_1$ ,6,7,8,9,10,11,12,13,14,15, $Q_3$ ,16,17,18,19,20

There are 10 values in between the first and third quartiles.

7 0

3 years ago

Math question what is the difference of 92 and 98

nexus9112 [7]

98-92=6

difference is 6

5 0

3 years ago