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Juli2301 [7.4K]
3 years ago
10

3 numbers that are less than 2 and greater then -1

Mathematics
1 answer:
Viefleur [7K]3 years ago
4 0

Three numbers less than 2, but greater than -1 are:

  • 0
  • 1
  • 1.5 (I don't know if that counts as a number specifically)


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2 math questions below!!!!
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Perimeter is 10 units while the area is 8 units I believe but that’s just by counting the boxes
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3 years ago
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(125,75)-(40,72) işleminin sonucunu bulunuz​
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85,03 çevap budur inşallah doğrudur iyi dersler

8 0
2 years ago
Remember to show work and explain. Use the math font.
vichka [17]

Answer:

\large\boxed{1.\ f^{-1}(x)=\sqrt[12]{3^x}}\\\\\boxed{2.\ f^{-1}(x)=\sqrt[4]{3^x}}\\\\\ \boxed{3.\ f^{-1}(x)=\sqrt[3]{4^{7-x}}}

Step-by-step explanation:

(a^n)^m=a^{nm}\\\\\log_ab=c\iff a^c=b\\\\a^{\log_ax}=x\\\\n\log_ab=\log_ab^n\\\\\log_ab+\log_ac=\log_a(bc)\\============================\\\\1.\\y=3\log_3x^4\to y=\log_3(x^4)^3\to y=\log_3x^{12}

2.\\y=\log_3x^4\\\\\text{Exchange x and y. Solve for y:}\\\\\log_3y^4=x\Rightarrow3^{\log_3y^4}=3^x\Rightarrow y^{4}=3^x\\\\y=\sqrt[4]{3^x}\\-------------------------

3.\\y=-\log_4x^3+7\\\\\text{Exchange x and y. Solve for y:}\\\\-\log_4y^3+7=x\qquad\text{subtract 7 from both sides}\\\\-\log_4 y^3=x-7\qquad\text{change the signs}\\\\\log_4y^3=7-x\Rightarrow4^{\log_4y^3}=4^{7-x}\\\\y^3=4^{7-x}\Rightarrow y=\sqrt[3]{4^{7-x}}

7 0
2 years ago
Choose all the fractions that are equivalent to1/7. (Click all that apply.)
Alchen [17]

Answer:

2/14, 4/28, 5/35, 7/70 or just 2/14

Step-by-step explanation:

Multiply both the numerator and denominator of 1/7 by 2, to get 2/14, or 2:14

And multiply the numerator and denominator of 1/7 by 3, to get 3/21, or 3:21. So 2:14 and 3:21 are two ratios that are equal to 1:7.

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4: Please help. What is the equation for ⨀C?
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It’s the second option
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