If f(x)=4-x^2 and h(x) is equivalent to (g-f)(3)
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Answer:
Expressions C and D correctly determine the markup price.
Step-by-step explanation:
A markup in mathematics is when an object's price is raised by a certain percentage. Therefore, because we are told that the telescope is originally $400 and is marked up by 32%, we can actually mathematically evaluate this.
When you markup a price, you multiply the original price by , where x is the percentage at which the object is marked up. However, x needs to be in decimal form for it to work out.
Therefore, with this new decimal, we can add 1 to it.
Finally, we multiply this result by the original price.
Therefore, we can already confirm that Expression C is one way to find the markup price.
- We can eliminate expression A because it did not use the formula
. It only uses the decimal form of the percentage.
- We can eliminate expression B because the division to convert from the percentage form to the decimal form is flawed (the expression divided by 10 instead of 100) and also forgot to add 1 to the determined value.
Now, we can test the math for expressions D and E to see if either of these will equal $528.
Expression D is basically saying to add 32% of 400 to the original price. This would work out because we marked up the original price by 32%. Therefore, we can confirm that Expression D is also an expression that can be used to determine the markup price.
Finally, we also need to check expression E. This expression is saying to add the already marked up price to 400. This would not be correct.
Therefore, it has been determined that Expression C & Expression D are both equations that will find a markup price.