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3 years ago

How to solve for linear equation 2/x+y/4=3/2

Mathematics

2 answers:

riadik2000 [5.3K]3 years ago

6 0

This problem is Not Linear

deff fn [24]3 years ago

3 0

Not linear. Hope this helps

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Which graph represents the solution set of this inequality?

lesya692 [45]

Answer:

the answer is C

Step-by-step explanation:

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3 years ago

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Nolan has some nickels and some dimes. He has no more than 19 coins worth no less than $1.30 combined. If Nolan has 5 nickels, d

Allushta [10]

Answer:

number of dimes 11 to 14

Step-by-step explanation:

given data

coin = 19

worth no less = $1.30

Nolan nickles = 5

solution

we convert 5 cent to dollars, it will be

5÷100 = $0.05

and

dime is worth 10 cents

so it will be 10 ÷ 100 = $0.1

so we consider here x as the number when nickels.

and we consider y as the number of dimes.

so here we can say

x + y ≤ 19 ..........................1

as here no less than $1.30 combined.

0.05 x + 0.1 y ≥ 1.3 ......................2

and

when Nolan has 5 nickels

put x = 5 in eq 1

5 + y ≤ 19

y ≤ 19 - 5

y ≤ 14

and

now we put x = 5 in eq 2

0.05 × 5 + 0.1y ≥ 1.3

0.25 + 0.1y ≥ 1.3

0.1y ≥ 1.3 - 0.25

0.1y ≥ 1.05

y ≥ 10.5

so all possible values for the number of dimes 11 to 14

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3 years ago

You want to order some T-shirts that cost $14 each. Shipping is $7 per order. If you buy 11 T-shirts, what will the order cost?

poizon [28]

14 x 11 = 154
7 x 11 = 77
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D divide 5 from 9 to get d

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4 years ago

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kvasek [131]

Answer:

5.89 mi/h

Step-by-step explanation:

This problem can be solved by using different methods. I will use vectors since it's the simplest way in which we can solve it. This can be solved by using related rates of change though.

First, we start by drawing a diagram with the velocity vectors.

A= velocity of the first person

B= velocity of the second person

C= velocity in which they are moving away from each other.

Since there is no acceleration in the problem, we can suppose we are talking about constant speeds, so the velocity at which they are moving away from each other will always remain constant. (It doesn't matter what time it is, the velocity will always be the same)

Having said this we can solve this problem by using the components, by using law of cosines or graphically. I will use law of cosines. The idea is to find the length of side c.

Law of cosines:

$C^{2}=A^{2}+B^{2}-2ABcos \gamma$