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olya-2409 [2.1K]
2 years ago
8

(2^7 .〖 5〗^8)/〖10〗^7

Mathematics
1 answer:
Tpy6a [65]2 years ago
7 0

Answer:

= 5.E14 im a genius mark me as brainliest

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Solve the system of equations. 4x + 2y = –14 6x + 3y = –22 (0, –7), (–1, –6), no solutions, infinitely many solutions. Plz and T
Marizza181 [45]

Answer:

no solutions

Step-by-step explanation:

4x + 2y = –14

6x + 3y = –22

Divide the first equation by 2 and the second equation by 3

4x/2 + 2y/2 = –14/2     2x +y = -7

6x/3 + 3y/3 = –22/3    2x + y = -22/3

The left hand sides are the same but the right hand sides are different.

Multiply the second equation by -1

2x+y = -7

-2x -y = 22/3

-------------------

0 = -7+22/3

0 = 1/3

This is never true, so there are no solutions

6 0
3 years ago
Read 2 more answers
The car is moving with a speed v0 = 48 mi/hr up the 4-percent grade, and the driver applies the brakes at point A, causing all w
lutik1710 [3]

Answer:

s = 0.2203 miles

Step-by-step explanation:

Given:

- The initial speed vo = 48 mi/hr

- The mass of the car m

- The coefficient of kinetic friction uk = 0.61

- The slope of the road 4-percent grade

Find:

Determine the stopping distance sAB. Repeat your calculations for the case when the car is moving downhill from B to A.

Solution:

- Apply the energy principle with work done against friction:

                             K.E_1 + P.E_1 = Wf + P_E_2 + K.E_2

- The final velocity of car is zero, K.E_2 = 0

  The initial potential energy is set as zero, P.E_1 = 0

                             K.E_1 = Wf + P_E_2

                             0.5*m*vo^2 = Ff*s + m*g*h

Where, Ff is the frictional force:

                             Ff = uk*N

Where, N is the normal contact force between car and road. By equilibrium equation we have:

                             m*g*cos(θ) - N = 0

                             N = m*g*cos(θ)

Hence,

                             Ff = uk*m*g*cos(θ)

- The vertical distance travelled h is:

                             h = s*sin(θ)

- The energy equation is:

                             0.5*m*vo^2 = uk*m*g*cos(θ)*s + m*g*s*sin(θ)

                             0.5*vo^2 = uk*g*cos(θ)*s + g*s*sin(θ)

                             s*(uk*g*cos(θ) + g*sin(θ) ) = 0.5*vo^2

                             s = [0.5*vo^2 / (uk*g*cos(θ) + g*sin(θ) ) ]

- The slope = 4 / 100,

                      s = [0.5*48^2 / (0.61*8052.97*cos(2.29) + 8052.97*sin(2.29) ) ]

                      s = 0.2203 miles

3 0
3 years ago
Guys help please again
Anon25 [30]
The answer is c and a
8 0
2 years ago
Please do answer: <br><br>Simplify the expression---5x-2y + 3x + 2y<br><br>(100 points)
netineya [11]
  • 5x-2y+3x+2y

Combine like terms

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  • (5+3)x+(-2+2)y
  • 8x+0
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8 0
2 years ago
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PLEASE HELP AS SOON AS POSIBLE
Tema [17]
I believe the answer should be f-there are 3/4 times as many cups of flour as there are cups of sugar
8 0
3 years ago
Read 2 more answers
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