50mph
Step-by-step explanation:
The image of the motion of Paul's derive is attached already.
From the line graph we can obtain a lot of information that will help us unravel the average speed of Paul within the given time frame.
What is average speed?
Average speed is the rate of change of total distance covered with time taken .
Average speed = 
To find the total distance covered;
Distance at time 1 = 75miles
Distance at time 4 = 225miles
Distance covered between 1 - 4 = 225 - 75 = 150miles
Time taken for the journey = 4 - 1 = 3hrs
Input the values in the equation;
Average speed = 
= 50mph
learn more:
Speed and motion brainly.com/question/10048445
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Answer:
I think it’s a
Step-by-step explanation:
First day: 25% × 100 = 25 ( miles)
Second day : the remaining distance is 100 - 25 = 75 ( milesl
Third day: 40% × 75 = 30
25 + 75 + 30 = 130 (miles)
Answer:
1/12
Step-by-step explanation:
The whole circumference (i.e complete circle) is an arc which measures 360°
in our case, it is given that our arc measures only 30°
the fraction of our arc of 30° to the complete circle of 360° is
30/360
= 3/36
= 1/12
Answer:
- P(t) = 100·2.3^t
- 529 after 2 hours
- 441 per hour, rate of growth at 2 hours
- 5.5 hours to reach 10,000
Step-by-step explanation:
It often works well to write an exponential expression as ...
value = (initial value)×(growth factor)^(t/(growth period))
(a) Here, the growth factor for the bacteria is given as 230/100 = 2.3 in a period of 1 hour. The initial number is 100, so we can write the pupulation function as ...
P(t) = 100·2.3^t
__
(b) P(2) = 100·2.3^2 = 529 . . . number after 2 hours
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(c) P'(t) = ln(2.3)P(t) ≈ 83.2909·2.3^t
P'(2) = 83.2909·2.3^2 ≈ 441 . . . bacteria per hour
__
(d) We want to find t such that ...
P(t) = 10000
100·2.3^t = 10000 . . . substitute for P(t)
2.3^t = 100 . . . . . . . . divide by 100
t·log(2.3) = log(100)
t = 2/log(2.3) ≈ 5.5 . . . hours until the population reaches 10,000
