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4 years ago

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Bijan has agreed to run a half-marathon to raise money for charity. Each day before school, Bijan runs a 2.4-mile route around h

is neighborhood. Then, each day after school, he runs on a lakeside trail. After 4 days, Bijan has run a total of 14.8 miles. Suppose you want to find out the length of the lakeside trail, x. What expression would represent how far Bijan runs everyday? What is the equation that represents his total distance after 4 days?

1 answer:

Slav-nsk [51]4 years ago

5 0

Answer:

First one is (x+2.4)

Second one is 4(x+2.4)=14.8

Step-by-step explanation:

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icating any part of this book is prohibited by law. Solve. 18. EXPLAIN Farzana knows that the additive identity property states

Dahasolnce [82]

Answer:

No, since when you multiply a number by 0, that means you are not adding that number to the sum which is 0. Since there is no addition going on, the answer is 0, so when you multiply any number by 0, the answer is 0.

Step-by-step explanation:

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1 year ago

1. Write a ratio and a percent for the shaded area. (1 point)

Kipish [7]

Answer:

3/10, 30%

Step-by-step explanation:

the shaded region is 9/30 which is equivilent to 3/10 and 3/10is 30 percent.

hope this helps!

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3 years ago

Elena has bought 320 tropical fish for a museum display. She bought 7 times as many triggerfish as parrotfish. How many of each

STALIN [3.7K]

The total number of fish bought was 320. And you know she bought two types of fish. The best way to solve this is guess and check. It would be the fastest. So she bought 7 times as many trigger-fish as parrot fish that means the number of trigger-fish bought was 7p. This means 320 = 7p +p. So all you do is take educated guesses for the number of parrot fish and check if it is right. So if she bought 50 parrot fish. 7(50) + 50 = 400. Close but a bit high. Lets keep guessing. 7(35) + 35 = 245. So now we know the answer is between 50 and 35. So lets try 40. 7(40) + 40 =320. That works so we know she bought 40 parrot fish and 280 trigger-fish.

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3 years ago

Solve for this equation:<br> x(x+3)(x+3)=0

Marta_Voda [28]

Answer:

x^3+6x^2+9x

if you are trying to find the original function

if not, and you are trying to find the zeros is

x=-3

x=0

Step-by-step explanation:

multiply x(x+3)

x^2+3x

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6 0

2 years ago

Read 2 more answers

The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,

uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

$\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right)$ .

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .

Notice that this equation is separable, then

$\frac{dP}{P(1-P/K)} = kdt$ .

Now, intagrating in both sides of the equation

$\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C$ .

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

$\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}$ .

So,

$\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|$ .

We have obtained that:

$-\ln\left| \frac{K-P}{P}\right| = kt +C$

which is equivalent to

$\ln\left| \frac{K-P}{P}\right|= -kt -C$

Taking exponentials in both hands:

$\left| \frac{K-P}{P}\right| = e^{-kt -C}$

Hence,

$\frac{K-P(t)}{P(t)} = Ae^{-kt}$ .

The next step is to substitute the given values in the statement of the problem:

$\frac{500-P(t)}{P(t)} = Ae^{-0.04t}$ .

We calculate the value of $A$ using the initial condition $P(0)=100$ , substituting $t=0$ :

$\frac{500-100}{100} = A}$ and $A=4$ .

So,

$\frac{500-P(t)}{P(t)} = 4e^{-0.04t}$ .

Finally, as we want the value of $t$ such that $P(t)=200$ , we substitute this last value into the above equation. Thus,

$\frac{500-200}{200} = 4e^{-0.04t}$ .

This is equivalent to $\frac{3}{8} = e^{-0.04t}$ . Taking logarithms we get $\ln\frac{3}{8} = -0.04t$ . Then,

$t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325$ .

So, the population of rats will be 200 after 25 months.

6 0

4 years ago