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guajiro [1.7K]
3 years ago
15

Find a linear transformation that maps the point (0; 0) to itself, the point (0; 1) to (����1; 1) and the point (1; 0) to (0;���

�10).
Mathematics
1 answer:
krek1111 [17]3 years ago
3 0
Liner 1.0 because its a tranformation 
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Guys I really need help with these too thanks u before!!!!
Natali5045456 [20]
Hey!!

here is your answer >>>

1) 3x - 10 > 11

let's take this as 3x - 10 = 11

3x = 21

x = 7
So, The numbers of X are always more than 7

2) 9x + 2 < 5

9x + 2 = 5

9x = 3

x = 1÷2

The numbers of X are always less than 1 ÷ 2

3) 2x + 8 < 6

2x + 8 = 6

2x = 2

x = 1

The numbers of X are less than 1

4) 4x - 3 < 12

4x - 3 = 12

4x = 15

x = 15 ÷ 4

The numbers of X are less than 15 ÷ 4

5) 2 ( 9 + x ) > 20

2 ( 9 + x ) = 20

9 + x = 10

x = 1

The numbers of X are more than 1

We can solve the rest using this

Hope my answer helps!
5 0
4 years ago
If a new soccer ball is labeled $45, what would the new price be if the sign above it says "63% off"?
Paul [167]

Answer:

New price of the ball after discount = $16.65

Step-by-step explanation:

Selling price of the soccer ball = $45

Discount labeled on the ball = 63% off

Therefore, selling price after the discount = Original selling price - %discount

= $45 - (63% of $45)

= $45 - $28.35

= $16.65

New price of the ball after discount = $16.65

3 0
3 years ago
Which slope is steeper 4/8 or 3/10 and why
pashok25 [27]

Answer:

4/8 is steeper than 3/10

Step-by-step explanation:

4 is half of 8 and in decimal form is 0.5. 3/10 in decimal form is 0.3. Therefore 0.5 is greater than 0.3, so 4/8 is considered to be steeper than 3/10.

8 0
3 years ago
Read 2 more answers
Lori creates the following design for a T-shirt.
kakasveta [241]

<u>Solution-</u>

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7


Area of rectangle 1 = 8.68 sq.in

\Rightarrow FH \times HI=8.68

\Rightarrow EB \times HI=8.68  (∵ sides of the rectangle 2)

\Rightarrow 2.8 \times HI=8.68

\Rightarrow HI=3.1


Area of Triangle 1 = 6.48 sq.in

\Rightarrow \frac{1}{2}\times AE \times EG= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+FG)= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+HI)= 6.48  (∵ sides of the rectangle 1)

\Rightarrow EF+3.1= 5.4

\Rightarrow EF=2.3

\Rightarrow BH=2.3  (∵ sides of the rectangle 2)


BC = BH+HI+IC

\Rightarrow 11.7= 2.3+3.1+IC

\Rightarrow IC=6.3


The area of Rectangle 2,

=EB\times BH =2.8\times 2.3=6.44\ sq.in


The area of Triangle 2,

\frac{1}{2}\times GI \times IC=\frac{1}{2}\times EB \times IC=\frac{1}{2}\times 2.8 \times 6.3=8.82\ sq.in


The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

= 6.48+8.68+8.82+6.44=30.42 sq.in


6 0
3 years ago
Subtract the following rational expressions
lesya692 [45]

\dfrac{2k}{3k-7} - \dfrac{3}{8k} = \dfrac{8k(2k)}{8k(3k-7)} - \dfrac{3(3k-7)}{8k(3k-7)}  =  \dfrac{8k(2k)-3(3k-7) }{8k(3k-7)} = \dfrac{16k^2 - 9k + 21}{24k^2-56}

5 0
4 years ago
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