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vichka [17]
2 years ago
9

Write the slope-intercept form of the equation of the line that passes through the given points.

Mathematics
2 answers:
zmey [24]2 years ago
8 0

Answer:

Slope=1

Step-by-step explanation:

Slope=y1-y2/x1-x2

Where x1,y1= (1, 1) and X2,y2=(-3, -3)

Slop=1+3/1+4

=4/4

=1

So the slope is 1.

tamaranim1 [39]2 years ago
6 0

Answer:

1

Step-by-step explanation:

Here,

x₁ = 1 and x₂ = (-3)

y₁ = 1 and y₂ = (-3)

Now,

<u>S</u><u>l</u><u>o</u><u>p</u><u>e</u><u> </u>

= y₁ - y₂ ÷ x₁ - x₂

= ( 1 ) - (- 3) ÷ ( 1 ) - (- 3)

= 1 + 3 ÷ 1 + 3

= 4 ÷ 4 = 1

Thus, Slope is 1

<u>-TheUnknown</u><u>Scientist</u>

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Dmitrij [34]

Answer:

-13

Step-by-step explanation:

just put -3 in stead of x in the given equation

and you'll get

-9-4=-13

6 0
3 years ago
A road running north to south crosses a road going east to west at the point P. Car A is driving north along the first road, and
Anettt [7]

Answer:

D^2 = (x^2 + y^2) + z^2

 

and taking derivative of each term with respect to t or time, therefore:

 

2*D*dD/dt  =  2*x*dx/dt  + 2*y*dy/dt  + 0 (since z is constant)

 

divide by 2 on both sides,

 

D*dD/dt = x*dx/dt + y*dy/dt

 

Need to solve for D at t =0,  x (at t = 0) = 10 km,  y (at t = 0) = 15 km

at t =0,

 

D^2 =  c^2 + z^2 = (x^2 + y^2) + z^2  =  10^2 + 15^2 + 2^2  = 100 + 225 + 4  = 329

 

D = sqrt(329)

 

Therefore solving for dD/dt, which is the distance rate between the car and plane at t = 0

 

dD/dt = (x*dx/dt + y*dy/dt)/D  =  (10*190 + 15*60)/sqrt(329)  = (1900 + 900)/sqrt(329)

 

= 2800/sqrt(329) = 154.4 km/hr

 

154.4 km/hr

Step-by-step explanation:

3 0
3 years ago
I will give brainlest please help should i write the answer differently? First answer gets brainlest
solmaris [256]

Answer:

15.6m

Step-by-step explanation:

FE is the hypotenuse, and we know the leg opposite of the angle, so we have to use the sin

sin = opposite/hypotenuse

hypotenuse * sin = opposite

hypotenuse = opposite / sin

FE = 10/0,64... = 15.6

5 0
3 years ago
will the contents of a cylindrical can of soup with a 1.5-inch radius and a 5-inch height fit into a pan with a 4-inch radius an
Anna007 [38]

Answer:

Answer: The volume of the soup can is less that that of the pan, so the soup will fit in the pan.

Step-by-step explanation:

a. V = s3

V = (7 km)3

V = 7 km × 7 km × 7 km

V = 343 km3

b. V = s3

V = (11 yd.)3

V = 11 yd. × 11 yd. × 11 yd.

V = 1,331 km cu. yd.

a. V = l × w × h

V = 6 m × 2 m × 3 m

V = 36 m3

b. V = l × w × h

V = 5 ft. × 10 ft. × 8 ft.

V = 400 cu. ft.

a. V = πr2h

V = 3.14 × (3 in.)2 × 3 in.

V = 3.14 × 9 sq. in. × 3 in.

V = 84.78 cu. in.

b. V = πr2h

V = 3.14 × (1 m)2 × 4 m

V = 3.14 × 1 m2 × 4 m

V = 12.56 m3

V = s3

V = (2 ft.)3

V = 2 ft. × 2 ft. × 2 ft.

V = 8 cu. ft.

Answer: The capacity of the ice chest is 8 cubic feet.

V = πr2h

V = 3.14 × (1 ft.)2 × 3 ft.

V = 3.14 × 1 sq. ft. × 3 ft.

V = 9.42 cu. ft.

Answer: The volume of the trash can is 9.42 cubic feet.

Closet #1

V = l × w × h

V = 4 ft. × 5 ft. × 8 ft.

V = 160 cu. ft.

Closet #2

V = l × w × h

V = 6 ft. × 3 ft. × 8 ft.

V = 144 cu. ft.

Compare the size of the closets

160 cu. ft. > 144 cu. ft.

Answer: The first closet is larger.

Both the can and the pan are cylindrical shapes. Compare the volumes of the two objects.

Volume of Can

V = πr2h

V = 3.14 × (1.5 in.)2 × 5 in.

V = 3.14 × 2.25 sq. in. × 5 in.

V = 35.325 cu. in.

Volume of Pan

V = πr2h

V = 3.14 × (4 in.)2 × 3 in.

V = 3.14 × 16 sq. in.× 3 in.

V = 150.72 cu. in.

35.325 cu. in. soup can < 150.72 cu. in pan

Answer: The volume of the soup can is less that that of the pan, so the soup will fit in the pan.

3 0
3 years ago
What is the ratio of 45 to 35
Mademuasel [1]
<span>35/45 = (7 x 5)/(9 x 5) = 7/9


</span>
8 0
3 years ago
Read 2 more answers
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