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castortr0y [4]
2 years ago
10

Using the diagram below, determine which statement is NOT true.

Mathematics
1 answer:
Ad libitum [116K]2 years ago
7 0

Answer: C

Step-by-step explanation:

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given \: equation \: is \: , \\  \\  {x}^{2}  - 12x + 20 = 0 \\  \\  using \: quadratic \: formula \: , \\  \\ x =  \frac{ - b +  \sqrt{ {b}^{2} - 4ac } }{2a}  \:  \:  \:  \:  =   \frac{ - ( - 12) +  \sqrt{ { (- 12)}^{2} - 4(1)(20) } }{2(1)} \\  \\ x =  \frac{ - b +  \sqrt{ {b}^{2} - 4ac } }{2a}  \:  \:  \:  \:  =   \frac{ - ( - 12)  -   \sqrt{ { (- 12)}^{2} - 4(1)(20) } }{2(1)} \\  \\ x =  \frac{12 + 8}{2}  \:  \:  \:  \:  \: or \:  \:  \:  \: x =  \frac{12 - 8}{2}  \\  \\ x = 10 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: x = 2 \:  \:  \: ans.
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Use the formula to evaluate the infinite series. Round to the nearest hundredth if necessary.
bagirrra123 [75]

Answer:

1.25.

Step-by-step explanation:

The common ratio r  is 1/5 and the first term a1 = (1/5)^(1-1) = 1.

Sum to infinity =  a1 / (1 - r)

=  1 / (1 - 1/5)

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the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 58 in, find its length and width
dolphi86 [110]

Answer:

  • Length = 17 inches

  • Width = 12 inches

⠀

Step-by-step explanation:

⠀

As it is given that, the length of a rectangle is 5 in longer than its width and the perimeter of the rectangle is 58 in and we are to find the length and width of the rectangle. So,

⠀

Let us assume the width of the rectangle as x inches and therefore, the length will be (x + 5) inches .

⠀

Now, <u>According to the Question :</u>

⠀

{\longrightarrow \qquad { \pmb{\frak {2 ( Length + Breadth )= Perimeter_{(Rectangle)} }}}}

⠀

{\longrightarrow \qquad { {\sf{2 ( x + 5 + x )= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{2 ( 2x + 5  )= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x + 10= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x = 58  - 10}}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x = 48}}}}

⠀

{\longrightarrow \qquad { {\sf{ x =  \dfrac{48}{4} }}}}

⠀

{\longrightarrow \qquad{ \underline{ \boxed { \pmb{\mathfrak {x = 12}} }}} }\:  \:  \bigstar

⠀

Therefore,

  • The width of the rectangle is 12 inches .

⠀

Now, We are to find the length of the rectangle:

{\longrightarrow \qquad{ { \frak{\pmb{Length = x + 5 }}}}}

⠀

{\longrightarrow \qquad{ { \frak{\pmb{Length = 12 + 5 }}}}}

⠀

{\longrightarrow \qquad{ { \frak{\pmb{Length = 17}}}}}

⠀

Therefore,

  • The length of the rectangle is 17 inches .

⠀

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