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Ivanshal [37]
3 years ago
15

Help pleasee ASAP !!

Mathematics
1 answer:
valina [46]3 years ago
3 0
An irrational number is a not-terminating and non repeating number.
\sqrt{7} is an irrational number.   
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What are the values of the side lengths of a triangle with 45-45-90
dalvyx [7]

Answer:

Looking at the graphic, if a 45-45-90 triangle has a hypotenuse of 1, then each of the side lengths equal 1 / square root (2)

Source: https://www.1728.org/trig2.htm

Step-by-step explanation:


8 0
3 years ago
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Evaluate the iterated integral 2 0 2 x sin(y2) dy dx. SOLUTION If we try to evaluate the integral as it stands, we are faced wit
nignag [31]

Answer:

Step-by-step explanation:

Given that:

\int^2_0 \int^2_x \ sin (y^2) \ dy dx \\ \\ \text{Using backward equation; we have:} \\ \\  \int^2_0\int^2_0 sin(y^2) \ dy \ dx = \int \int_o \ sin(y^2) \ dA \\ \\  where; \\ \\  D= \Big\{ (x,y) | }0 \le x \le 2, x \le y \le 2 \Big\}

\text{Sketching this region; the alternative description of D is:} \\ D= \Big\{ (x,y) | }0 \le y \le 2, 0 \le x \le y \Big\}

\text{Now, above equation gives room for double integral  in  reverse order;}

\int^2_0 \int^2_0 \ sin (y^2) dy dx = \int \int _o \ sin (y^2) \ dA  \\ \\ = \int^2_o \int^y_o \ sin (y^2) \ dx \ dy \\ \\ = \int^2_o \Big [x sin (y^2) \Big] ^{x=y}_{x=o} \ dy  \\ \\=  \int^2_0 ( y -0) \ sin (y^2) \ dy  \\ \\ = \int^2_0 y \ sin (y^2) \ dy  \\ \\  y^2 = U \\ \\  2y \ dy = du  \\ \\ = \dfrac{1}{2} \int ^2 _ 0 \ sin (U) \ du  \\ \\ = - \dfrac{1}{2} \Big [cos  \ U \Big]^2_o \\ \\ =  - \dfrac{1}{2} \Big [cos  \ (y^2)  \Big]^2_o  \\ \\ =  - \dfrac{1}{2} cos  (4) + \dfrac{1}{2} cos (0) \\ \\

=  - \dfrac{1}{2} cos  (4) + \dfrac{1}{2} (1) \\ \\  = \dfrac{1}{2}\Big [1- cos (4) \Big] \\ \\  = \mathbf{0.82682}

5 0
3 years ago
X^2 + y^2 - 6y + 4x = 36
zysi [14]
It is AAaaaaaaaaaaaaaaaaaa
6 0
3 years ago
Niko uses 12 marshmallows and 8 graham crackers to make 4 s'mores.
Lerok [7]

Answer:

6 crackers, 9 marshmallows

Step-by-step explanation:

You have to divide to find how many graham crackers and marshmallows are needed to make 1 s'more:

8 / 4 = 2, so 2 crackers per s'more. Then,

12 / 4 = 3, so 3 marshmallows per s'more. Now that we know this, all we have to do is multiply each number by 3 to make 3 s'mores.

2 * 3 = 6, so 6 crackers, and

3 * 3 = 9, so 9 marshmallows.

:)

3 0
3 years ago
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Help me out with these please!<br><br> No links to suspicious sites!
weeeeeb [17]

Answer:

1) N = 2. 2) -7/3

Step-by-step explanation:

1)

6 = 3n

6/3 = n

2 = n

n = 2

2)

-3 = 3t + 4

3t + 4 = -3

3t = -3 - 4

3t = -7

T = -7/3

5 0
3 years ago
Read 2 more answers
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