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3 years ago

HELP PLEASE THANK U BAES

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

4 0

Answer:

Step-by-step explanation:

y-y1=m(x-x1)

y1= y-coordinate of a point

(-2,1)

the y-coordinate is 1

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Scores on a university exam are Normally distributed with a mean of 78 and a standard deviation of 8. The professor teaching the

mafiozo [28]

Answer:

Porcentage of students score below 62 is close to 0,08%

Step-by-step explanation:

The rule

68-95-99.7

establishes:

The intervals:

[ μ₀ - 0,5σ , μ₀ + 0,5σ] contains 68.3 % of all the values of the population

[ μ₀ - σ , μ₀ + σ] contains 95.4 % of all the values of the population

[ μ₀ - 1,5σ , μ₀ + 1,5σ] contains 99.7 % of all the values of the population

In our case such intervals become

[ μ₀ - 0,5σ , μ₀ + 0,5σ] ⇒ [ 78 - (0,5)*8 , 78 + (0,5)*8 ] ⇒[ 74 , 82]

[ μ₀ - σ , μ₀ + σ] ⇒ [ 78 - 8 , 78 +8 ] ⇒ [ 70 , 86 ]

[ μ₀ - 1,5σ , μ₀ + 1,5 σ] ⇒ [ 78 - 12 , 78 + 12 ] ⇒ [ 66 , 90 ]

Therefore the last interval

[ μ₀ - 1,5σ , μ₀ + 1,5 σ] ⇒ [ 66 , 90 ]

has as lower limit 66 and contains 99.7 % of population, according to that the porcentage of students score below 62 is very small, minor than 0,15 %

100 - 99,7 = 0,3 %

Only 0,3 % of population is out of μ₀ ± 1,5 σ, and by symmetry 0,3 /2 = 0,15 % is below the lower limit, 62 is even far from 66 so we can estimate, that the porcentage of students score below 62 is under 0,08 %

6 0

2 years ago

What are the solutions to the equation 3(x – 4)(x + 5) = 0?

iris [78.8K]

Answer:

x=4 and x= - 5

Step-by-step explanation:

In order to solve this we should re-arrange the equation:

$(x-4)(x+5)=\frac{0}{3}$

This is equal to:

$(x-4)(x+5)=0$

Then we can seperate this into:

$(x-4)=0\\(x+5)=0$

So solving for x in both cases we get

$x-4=0 \\x=4\\And\\x+5=0\\x=-5\\$

4 0

2 years ago

The spinner shown has eight equal-sized sections. The pointer lands on an even number 135 times out of 250 spins. Which of the f

forsale [732]

Answer:

A and D

Step-by-step explanation:

Here, we shall be evaluating the validity of the statements;

A. Yes, A is true

There are four even numbers 2,4,6 and 8 and 4 odd number 1,3,5,7; The landing should be equal at 125 each

B. This is wrong

It is supposed to land half of the number of time s which is half of 250 and that is 125

C.This is wrong

The numbers greater than 4 are 5,6,7,8

Now, the probability should be 4/8 = 1/2 and that is 50%

D. This is correct

Number of times we have a landing on odd numbers is 250-135 = 115

The experimental probability of landing on an odd number is thus 115/250 = 0.46 which is 46%

8 0

3 years ago

Can someone help me with the working out please its due Tomorrow

slavikrds [6]

1) 12p+12q 2) 11p-11q 3)2p-10q

3 0

3 years ago

Quadrilateral ABCD has the following vertices.

Marizza181 [45]

A(-5,5)
B(4,5)
C(2,0)
D(-5,-2)

AB,BC,CD,DA

AB = [4-(-5)),5-5]=[9,0]
Lenght $AB= \sqrt{9^2+0^2}= \sqrt{81} =9$

BC = [2-4,0-5]=[-2,-5]
Lenght $BC=\sqrt{(-2)^2+(-5)^2}=\sqrt{4+25}=\sqrt{29}$

CD = [-5-2,-2-0]=[-7,-2]
Lenght $CD=\sqrt{(-7)^2+(-2)^2}=\sqrt{49+4}=\sqrt{53}$

DA =[-5-(-5),-2-5]=[0,-7]
Lenght $DA=\sqrt{0^2+(-7)^2}=\sqrt{49}=7$

sorted from longest to shortest:
AB, CD,DA,BC
$\sqrt{81}, \sqrt{53}, \sqrt{49}, \sqrt{29}$

3 0

2 years ago