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Natasha2012 [34]
3 years ago
11

Help with this math question

Mathematics
1 answer:
Anna35 [415]3 years ago
3 0

Answer:

Step-by-step explanation:

In the first triangle, you have the following relation between a, b and h.

\frac{a}{h} = \frac{h}{b}

This is another form of the Altitude Theorem in a right triangle.

In the second example, we use the Altitude Theorem:

Let h denote the dotted line / the altitude;

h^2 = 7 \cdot 9 = 36

h = 6, we take the positive version since we're in Euclidean Geometry.

Now we have to solve for x. It's easy since the h that we solved for is in a right triangle and we have Pythagora's Theorem for that.

It states: x^2 = 6^2 + 9^2 = 117

So x = \sqrt{117}

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6y = 12
y = 12/6
y = 2

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Is the sum of two rational numbers always rational
Pepsi [2]

Answer:

in short, Yes they are always rational.

here's why...

E.g. suppose \frac{c}{d} and \frac{a}{b} are fractions, that means that a,b,c,d are all integers, and b and d are not zero. finding the sum the numerator, and denominator would also have to be integers. the denominator of the sum can't be zero since the denominators of the fractions were not zero, and would give \frac{ad+bc}{bd} and since they are bound by addition (sum means addition) they must also be rational since eit would equal a bigger integer than initially had

Step-by-step explanation:

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2 years ago
Bob makes 4% commission on his sales as a real estate agent. If Bob sells a house for $249,000, how much money does he get to ke
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He gets to keep $9,960 of the sale
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3 years ago
Factor as the product of two binomials.<br> 22 + 11x + 18
Dahasolnce [82]

Answer:

11x +40

Step-by-step explanation:

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4 0
3 years ago
Help me please. I am having troubles with my math homework.
jeyben [28]

Answer: (3) f(8) = g(8)

<u>Step-by-step explanation:</u>

Let's compare the values of f(x) and g(x) when x = 0, 2, 8, and 4

<u>      f(x)       </u>                      <u>      g(x)        </u>            <u>Comparison</u>

f(x) = 2x - 3                     g(x)=\dfrac{3}{2}x+1

f(0) = 2(0) - 3                     g(0)=\dfrac{3}{2}(0)+1

      = -3                                   = 1                     f(0) < g(0)

f(2) = 2(2) - 3                     g(2)=\dfrac{3}{2}(2)+1

     = 1                                      = 4                     f(2) < g(2)

f(8) = 2(8) - 3                     g(8)=\dfrac{3}{2}(8)+1

     = 13                                   = 13                     f(8) = g(8)

f(4) = 2(4) - 3                     g(4)=\dfrac{3}{2}(4)+1

      = 5                                   = 7                       f(4) < g(4)


The only statement provided that is true is f(8) = g(8)




3 0
3 years ago
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