Step-by-step explanation:
<u>In isocseles triangle, base angles </u><u>are</u><u> equal</u> :
base angles are angle N and angle P:
angle N=angle P
3x+17=4x+2
4x-3x=17-2
x=15
<u>F</u><u>o</u><u>r</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>N</u><u>:</u>
subtitute x in angle N
=3(15)+17
=45+17
=62
<u>F</u><u>o</u><u>r</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>P</u><u>:</u>
subtitute x in angle P:
=4(15)+2
=60+2
=62
<u>F</u><u>o</u><u>r</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>O</u><u>:</u>
sum of all angles in a triangle is 180.
angle N +angle P+angle O=180
62+62+angle O=180
angle O=180-62-62
angle O=56
<u>N</u><u>o</u><u>t</u><u>e</u><u>:</u><u> </u><u>i</u><u>f</u><u> </u><u>y</u><u>o</u><u>u</u><u> </u><u>have</u><u> </u><u>any</u><u> </u><u>question</u><u> </u><u>l</u><u>e</u><u>t</u><u> </u><u>m</u><u>e</u><u> </u><u>k</u><u>n</u><u>o</u><u>w</u><u> </u><u>a</u><u>b</u><u>o</u><u>u</u><u>t</u><u> </u><u>i</u><u>t</u><u>.</u><u> </u><u>t</u><u>h</u><u>a</u><u>n</u><u>k</u><u>s</u>
Answer:
1/3
Step-by-step explanation:
7-9x=(x+3)+2x
7-9x=x+3+2x
7-3=x+2x+9x
4=12x
x=1/3
Answer:
The roots of the given equation are x = 0 and x = -8.
General Formulas and Concepts:
<u>Algebra I</u>
Terms/Coefficients
Quadratic Equations
- Solving quadratic equations
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify.</em>
y = x² + 8x
<u>Step 2: Find Roots</u>
- [Quadratic] Factor: y = x(x + 8)
- [Quadratic] Set up [Solve]: 0 = x(x + 8)
- [Quadratic] Define: x = 0, -8
∴ the roots of the quadratic equation y = x² + 8x is equal to 0 and -8.
---
Topic: Algebra I
Answer:
Part 1) 
Part 2) Yes, It is a 30-60-90 triangle
Step-by-step explanation:
The picture of the question in the attached figure
Part 1) How long is JL?
we know that
In the right triangle JKL
---> by TOA (opposite side divided by adjacent side)
we have


substitute the given values


Part 2) This is a 30-60-90 triangle?
Find the measure of angle J
we know that
---> by complementary angles in a right triangle
we have

substitute


therefore
The right triangle JKL is a 30-60-90 triangle
You didnt give the sizes of the ribbon so let me help you out. You have to divide the size by total cost, bringing you to the cost per one whatever unit you are using.