1. Answer (D). By the law of sines, we have 
in any 
2. Answer (C). The law of cosines, 
accepts up to three sides and an angle as an input.
3. Answer (D). Although this triangle is right, we are not given enough information to uniquely determine its sides and angles - here, we need either one more side or one more angle.
4. Answer (D). Don't get tripped up by answer choice (C) - this is just a rearrangement of the statement of the law of cosines. In choice (D), the signs of 
and 
are reversed.
5. Answer (B). By the law of sines, we have 
Solving gives 
Note that this is the <em>ambiguous (SSA) case</em> of the law of sines, where the given measures could specify one triangle, two triangles, or none at all!
6. Answer (A). Since we know all three sides and none of the angles, starting with the law of sines will not help, so we begin with the law of cosines to find one angle; from there, we can use the law of sines to find the remaining angles.
Answer:
Imperfect substitutes
explanation:
The choices above are not perfect substitutes, meaning they can not be perfectly or directly replace the other. Imperfect substitutes are close substitutes but not perfect substitutes. Unlike perfect substitutes, imperfect substitutes satisfies same utility but has different characteristics and therefore not entirely substitutable. For example, while one may want to have the 40 marks too, he'd rather have 60 marks even if the criteria for a 60 mark score was increasingly hard.
Answer:
V=3888 in³
Step-by-step explanation:
V=πr^2h
V=π x 7.5^2 x 22
V=3888 in³
Surface area of square pyramid having square base side = 10 cm and slant height = 20 cm is 340 square meters
<u>Solution:</u>
Given that
Shape of the roof is square pyramid.
Base length of square pyramid roof = 10 meters
Slant height of square pyramid roof = 12 meters
Need to calculate the surface area of the roof
Where s is side of square base and l is slant height.
In our case s = 10 meters and l = 12 meters
On substituting the given values in formula we get
Surface area of square pyramid 
Hence surface area of square pyramid having square base side = 10 cm and slant height = 20 cm is 340 square meters.
The top and sides of the cylinder have an area of pr^2+2prh, but the pr^2 of the top is also removed from the cube which has an area of 6s^2.
A=6s^2+2prh
A=6*36+2p4*1
A=216+8p in^2
A≈241.13 in^2 (to nearest one-hundredth)
Note that I did not include the area of the cylinder that touches the cube...
