If you get it right, you get a brainliness!

The ratio of Harry's money to Lincoln's money is 6:5. If Harry and Lincoln have a total of $220, how much money in dollars does

nydimaria [60]

Answer:

Harry has 120$

Step-by-step explanation

6x+5x=220

11x=220

/11 /11

x=20

6 * 20 = 120

I'd apptreciate help w my questions if u can :)

7 0

3 years ago

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On a coordinate plane, two parabolas open up. The solid-line parabola, labeled f of x, goes through (negative 2, 4), has a verte

statuscvo [17]

Answer:

Option 4.

Step-by-step explanation:

The vertex form of a parabola is

$g(x)=a(x-h)^2+k$ ... (1)

where, a is a constant (h,k) is vertex.

The given function is

$f(x)=x^2$

The vertex of the function is (0,0) and it goes through (-2, 4) and (2, 4).

It is given that the vertex of function g(x) is at (5,2).

Substitute h=5 and k=2 in equation.

$g(x)=a(x-5)^2+2$

g(x) is passes through (3, 6).

$6=a(3-5)^2+2$ .... (2)

$6-2=4a$

$4=4a$

Divide both sides by 4.

$a=1$

Substitute a=1 in equation (2).

$g(x)=1(x-5)^2+2$

$g(x)=(x-5)^2+2$

The function g(x) is $g(x)=(x-5)^2+2$ .

Therefor, the correct option is 4.

3 0

3 years ago

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Mr. Peate is building a rectangular fence around his house. The fence will be 32 feet long and 29 feet wide. What will be the pe

kupik [55]

Answer:

112

Step-by-step explanation:

32*2+29*2=112

8 0

3 years ago

A rectangular swimming pool is bordered by a concrete patio. the width of the patio is the same on every side. the area of the s

andre [41]

Answer:

$x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right)$

where

l = length of the pool (w/o the patio)
w = width of the pool (w/o the patio)

Explanation:

Let

x = width of the patio
l = length of the pool (w/o the patio)
w = width of the pool (w/o the patio)

Since the pool is bordered by a complete patio,

Length of the pool (with the patio)
= (length of the pool (w/o the patio)) + 2*(width of the patio)
Length of the pool (with the patio) = l + 2x

Width of the pool (with the patio)
= (width of the pool (w/o the patio)) + 2*(width of the patio)
Width of the pool (with the patio) = w + 2x

Note that

Area of the pool (w/o the patio)
= (length of the pool (w/o the patio))(width of the pool (w/o the patio))
Area of the pool (w/o the patio) = lw

Area of the pool (with the patio)
= (length of the pool (w/o the patio))(width of the pool (w/o the patio))
= (l + 2x)(w + 2x)
= w(l + 2x) + 2x(l + 2x)
= lw + 2xw + 2xl + 4x²
Area of the pool (with the patio) = 4x² + 2x(l + w) + lw

Area of the patio
= (Area of the pool (with the patio)) - (Area of the pool (w/o the patio))
= (4x² + 2x(l + w) + lw) - lw
Area of the patio = 4x² + 2x(l + w)

Since the area of the patio is equal to the area of the surface of the pool, the area of the patio is equal to the area of the pool without the patio. In terms of the equation,

Area of the patio = Area of the pool (w/o the patio)
4x² + 2x(l + w) = lw
4x² + 2x(l + w) - lw = 0 (1)

Let

a = numerical coefficient of x² = 4
b = numerical coefficient of x = 2(l + w)
c = constant term = -lw

Then using quadratic formula, the roots of the equation 4x² + 2x(l + w) - lw = 0 is given by

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\\ = \frac{-2(l + w) \pm \sqrt{(2(l + w))^2 - 4(4)(-lw)}}{2(4)} 
\\ = \frac{-2(l + w) \pm \sqrt{(4(l + w)^2) + 16lw}}{8} 
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 2lw + w^2) + 4(4lw)}}{8}
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 2lw + w^2 + 4lw)}}{8}
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 6lw + w^2)}}{8}$
$= \frac{-2(l + w) \pm 2\sqrt{l^2 + 6lw + w^2}}{8} \\= \frac{2}{8}(-(l + w) \pm \sqrt{l^2 + 6lw + w^2}) \\x = \frac{1}{4}(-(l + w) \pm \sqrt{l^2 + 6lw + w^2}) \\\boxed{x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right) \text{ or }}
\\\boxed{x = -\frac{1}{4}\left((l + w) + \sqrt{l^2 + 6lw + w^2} \right)}$

Since $(l + w) + \sqrt{l^2 + 6lw + w^2} \ \textgreater \ 0$ , $-\frac{1}{4}\left((l + w) + \sqrt{l^2 + 6lw + w^2}\right)$ is negative. Since x represents the patio width, x cannot be negative. Hence, the patio width is given by

$\boxed{x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right)}$

7 0

3 years ago

Which trend line has been drawn correctly using the divide-center method?

dangina [55]

Answer:

I'm pretty sure its C but some please correct me if I'm wrong.

3 0

3 years ago

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