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Anit [1.1K]
3 years ago
8

A truck driver is driving from Nome, Alaska to Death Valley, California. Because he is traveling between locations with extreme

temperatures, he needs to check the weather continuously to make sure the gas in his truck remains in liquid form. The gas he uses freezes at −40° F and evaporates at 140° F. Part A: Write an inequality to represent the temperatures at which the gas in the truck will remain in liquid form. Part B: Describe the graph of the inequality completely from Part A. Use terms such as open/closed circles and shading directions. Explain what the solutions to the inequality represent. Part C: In January 1989, the temperature in Nome, Alaska dropped to −49° F. Would the gas in the driver's truck have remained in liquid form so he could have driven on this day? Why or why not?
​
Mathematics
2 answers:
konstantin123 [22]3 years ago
6 0

Answer:

idk

Step-by-step explanation:

Debora [2.8K]3 years ago
6 0

Answer:

answer below

Step-by-step explanation:

Part A: The temperature must be greater than -40, and lower than 140.  -40 < T < 140

Part B: The graph is a number line between -40 and 140, with open circles at -40 and 140.  The solutions are temperatures at which the gas will remain liquid.

Part C: No, -49 is less than -40, so the gas would have frozen.

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Answer:

E (X) = 1.8

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Step-by-step explanation:

Solution:-

- Denote the random variable X : is the number of red marbles that Suzan has in her hand after she selects three marbles.

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X = 2 red marble:

        P ( X = 2 ) : Suzan chooses 2 Red marble from the available 3 red marble and 1 green marbles.

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- The variance Var(X) for the given random variable X is:

                Var ( X ) = ∑Xi^2*P(Xi) - [ E(X) ] ^2

                               = 1^2*0.3 + 2^2*0.6 + 3^2*0.1 - 1.8^2

                               = 0.36

- The standard deviation for the given random variable X is:

                σ = √Var(X)

                σ = √0.36

                σ = 0.6

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