Question

The figure is made up of a cylinder, a cone, and a half sphere. The radius of the half sphere is 3 inches. What is the volume of the composite figure?

Answer 1

Given.

Radius of the Half sphere is 3 inches.

From the figure;

Radius of half sphere= Radius of cylinder= Radius of cone=3inches

Height of cone= 4inches.

Height of cylinder=6inches.

Volume of cone=(πr²h)/3

=(π3²×4)/3

=(12π) inch³

volume of cylinder= πr²h=π3²6=54π inch³

Volume of half sphere= (4/3) π r³=π(4×3³)/3 (1/2)=π×4×9/2=18π inch³

Total area of Composite figure=(12π +54π +18π) inch³

=84π inch³

=(84)× 22/7inch³

=12×22 inch³

=264inch³

Hope it helps...

Regards;

Leukonov/Olegion.

Answer 2

Answer:

The volume of the composite figure is 84π ≅ 263.89 inches³

Step-by-step explanation:

Lets revise the rules of the volume of some figures

- The composite figure consists of :

# Half sphere with radius 3 inches

# Cylinder with radius 3 inches and height 6 inches

# Cone with radius 3 inches and height 4 inches

- The volume of the sphere is 4/3 π r³

∴ The volume of the half sphere = 1/2 × 4/3 π r³ = 2/3 π r³

- The volume of the cylinder is π r² h

- The volume of the cone is 1/3 π r² h

* Now lets solve the problem

- The volume of the half sphere

∵ The radius of the half sphere = 3 inches

∵ The volume of it = 2/3 π r³

∴ The volume = 2/3 × π × (3)³ = 18π inches³

- The volume of the cylinder

∵ The radius of the cylinder = 3 inches

∵ The height of the cylinder = 6 inches

∵ The volume of it = π r² h

∴ Its volume = π × (3)² × 6 = 54π inches³

- The volume of the cone

∵ The radius of the cone = 3 inches

∵ The height of the cone = 4 inches

∵ The volume of it = 1/3 π r² h

∴ Its volume = 1/3 π × (3)² × 4 = 12π inches³

- Add all the volumes to find the volume of the composite figure

∴ The volume = 18π + 54π + 12π = 84π = 263.89 inches³

* The volume of the composite figure is 84π ≅ 263.89 inches³