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2 years ago

Y=-2(x-3)^2 +10 Y=4x

Mathematics

1 answer:

shepuryov [24]2 years ago

7 0

Answer:

i might be wrong but 8 if not (2,8) if not sorry

Step-by-step explanation:

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X + 6 = 2x - 8 x= solve for x

nata0808 [166]

Step-by-step explanation:

x + 6 = 2x - 8

1. Subtract 2x from both sides

x - 2x + 6 = 2x - 2x - 8

2. Simplify

-x + 6 = -8

3. Now, subtract 6 from both sides

-x + 6 - 6 = -8 - 6

4. Simplify

-x = -14

5. Divide both sides by -1 because you would want the x by itself instead of having -x

-1x/-1 = -14/-1

6. Simplify

x = 14 <------ Answer

Hope that helped!!

~Shane

8 0

3 years ago

John's garden is 12ft long and 15ft wide. How long is John's garden in yards?

kkurt [141]

Answer:

4 yards long

Step-by-step explanation:

John's garden is 12 ft long and 3 ft go into a yard. With this information you then divide 12 by 3 to see how many yards would go into the 12. 12/3=4

6 0

3 years ago

Read 2 more answers

Please only answer if you know the answer.

yarga [219]

Answer:

F=First

O=Outer

I=Inner

L=Last

8 0

2 years ago

Read 2 more answers

Factor: x^2 + 9x - 36 = 0

alexdok [17]

Answer:

I'm pretty sure it's x = 12, -3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

B. Determine the values of a and b so that f is continuous. Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

3 years ago