Ask question

Ask question

All categories

3 years ago

7

I need to find what m

1 answer:

Sav [38]3 years ago

7 0

If BC = EC than Angle BEC = Angle CBE = 66.
Then Angle BCE = 180 - 66 - 66 = 48
Angle DCF = BCE = 48.
So Angle FCA = 180 - 48 = 132.

You might be interested in

I really need help with the question above! This is my second time asking. Am I right? If not please give me the correct answer

vredina [299]

Hey there! :D

Pay attention to the given angles.

We know that a circle is equal to 360 degrees.

We know two angles, and the other 2 are the same measure.

170+44= 214

Subtract that from 360, since that is what the circle equals.

360-214= 146

Divide that by two, since there are 2 equal angles left.

146/2= 73

<DOB= 73 degrees.

You were correct, so good work!

I hope this helps!
~kaikers

4 0

3 years ago

Sarah and Bryan went shopping and spend a total of $47.50. Bryan spends $15.50 less than was Sarah spent. How much did Bryan spe

myrzilka [38]

X+(x+15.50)=47.50
2x=32
x=16
Bryan spends $16

3 0

3 years ago

Read 2 more answers

May u please help me ill give out the brainly

Sedaia [141]

Answer: The answer that I think is A

sry if wrong

8 0

2 years ago

Read 2 more answers

Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye

svetlana [45]

Answer:

The required recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

$Year \: 1 = 500$

Each year thereafter the number of leaves was 40% more than the year before so that means

$Year \: 2 = 500(1+0.40) = 500\times 1.4\\$

For the third year the number of leaves increase 40% than the year before so that means

$Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\$

Similarly for fourth year,

$Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\$

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

$f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330$

So there will be 10330 leaves in the 10th year.

3 0

3 years ago

Read 2 more answers

Determine if the following system of equations has no solutions, infinitely many

mylen [45]

This are similar answers to your questions.

8 0

2 years ago