Answer:
Atomic mass of Ag-107 = 106.94 amu
Explanation:
Let the mass of Ag-107 be y
Since the mass ratio of Ag-109/Ag-107 is 1.0187, the mass of Ag-109 is 1.0187 times heavier than the mass of Ag-107
Mass of Ag-109 = 1.0187y
Relative atomic mass of Ag = sum of (mass of each isotope * abundance)
Relative atomic mass of Ag = 107.87
Abundance of Ag-107 = 51.839% = 0.51839
Abundance of Ag-109 = 41.161% = 0.48161
107.87 = (y * 0.51839) + (1.018y * 0.48161)
107.87 = 0.51838y + 0.49027898y
107.87 = 1.00865898y
y = 107.87/1.00865898
y = 106.94 amu
Therefore, atomic mass of Ag-107 = 106.94 amu
The answer is
<span>Fe3+ + e- Fe2+ = 0.77 V</span>
Answer:
n = 0.3 mol
Explanation:
Given data:
Volume of gas = 8.0 L
Temperature of gas = 45 °C (45+273 = 318 K)
Pressure of gas = 0.966 atm
Moles of gas present = ?
Ideal gas constant = R = 0.021 atm.L/mol.K
Solution:
Formula:
PV = nRT
P = Pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
Now we will put the values:
0.966 atm × 8 L = n × 0.0821 atm.L/mol.K × 318 K
7.728 atm.L = n × 26.12 atm.L/mol
7.728 atm.L / 26.12 atm.L/mol = n
n = 0.3 mol
Answer:
Option D
Explanation:
A solution is neutral if it contains equal concentrations of hydronium and hydroxide ions; acidic if it contains a greater concentration of hydronium ions than hydroxide ions; and basic if it contains a lesser concentration of hydronium ions than hydroxide ions.
A common means of expressing quantities, the values of which may span many orders of magnitude, is to use a logarithmic scale.
The hydroxide ion molarity may be expressed as a p-function, or pOH.
pOH = −log[OH−]
Basic solutions are those with hydronium ion molarities less than 1.0 × 10−7 M and hydroxide ion molarities greater than 1.0 × 10−7 M (corresponding to pH values greater than 7.00 and pOH values less than 7.00).
