600.0 mL of a gas is collected at 845.0 mmHg. What will the volume be at standard pressure?
1 answer:
Answer:
667.105ml
Explanation:
V1VP1 / V2P2
V2=V1P1 / P2
Pressure at S.T.P is 760
V2= 600×845/760
V2=667.105ml
Therefore V2 = 667.105ml approximately
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