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Nezavi [6.7K]
2 years ago
7

Hypothesis and Data Collection Fill the balloon with water until it is the size of a golf ball, and tie a knot in the end. Make

sure there are no air bubbles in the balloon. In the plastic container, mix the plaster of Paris powder with water until it is as thick as yogurt, and then press the balloon into the center. One-third of the balloon should be below the surface of the plaster. Set the container aside until the plaster sets. Part A In this experiment, you will place the container in the freezer. What do you think will happen?
Chemistry
1 answer:
Alika [10]2 years ago
4 0

Hypothetically speaking, we can infer and logically deduce that the water is most likely to expand.

<h3>What is an experiment?</h3>

An experiment can be defined as a scientific investigation which typically involves the process of manipulating an independent variable (the cause), so as to determine or measure the dependent variable (the effect).

<h3>The states of matter.</h3>

In Science, water is an example of matter and it exists in three (3) main states or phases such as the following:

  • Solid
  • Liquid
  • Gas

Based on scientific records and information, we know that all particles have various degrees of attraction to one another. Also, water is a liquid and as such the attraction between its particles is strong enough to hold them together, but not strong enough to prevent the particles from sliding past each other.

In conclusion, we can infer and logically deduce that the water is most likely to expand in accordance with the kinetic-molecular theory of matter.

Read more on matter here: brainly.com/question/2773301

#SPJ1

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What is the entropy change of the system when 17.5 g of liquid benzene (C6H6) evaporates at the normal boiling point? The normal
Ksivusya [100]

Answer : The entropy change of the system is, 19.5 J/K

Solution :

First we have to calculate the moles of benzene.

\text{Moles of }C_6H_6=\frac{\text{Mass of }C_6H_6}{\text{Molar mass of }C_6H_6}=\frac{17.5g}{78.11g/mole}=0.224moles

Now we have to calculate the entropy change of the system.

Formula used :

\Delta S=\frac{n\times \Delta H_{vap}}{T_b}

where,

\Delta S = entropy change of the system = ?

\Delta H = enthalpy of vaporization = 30.7 kJ/mole

n = number of moles of benzene  = 0.224 mole

T_b = normal boiling point of benzene = 80.1^oC=273+80.1=353.1K

Now put all the given values in the above formula, we get the entropy change of the system.

\Delta S=\frac{0.224mole\times (30.7KJ/mole)}{353.1K}=0.0195kJ/K=0.0195\times 1000=19.5J/K

Therefore, the entropy change of the system is, 19.5 J/K

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What is the molality of an aqueous solution that contains 29.5 g of glucose (C6H12O6) dissolved in 950 g of water (H2O)?
Gnesinka [82]
Molality is one way of expressing concentration of a solute in a solution. It is expressed as the mole of solute per kilogram of the solvent. To calculate for the molality of the given solution, we need to convert the mass of solute into moles and divide it to the mass of the solvent.

Molality = 29.5 g glucose (1 mol / 180.16 g ) / .950 kg water
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