Answer:
The events being a heavy smoker and having emphysema are not independent.
Step-by-step explanation:
We are given the following in the question:
Number of women = 2000
Number of heavy smoker = 340
Number of women who has emphysema = 25
Number of women who has emphysema and are heavy smoker = 21
P(Smoker) =

P(emphysema) =

P(Smoker and emphysema) =

Two events A and B are said to be independent if

Checking conditions for independence:

Thus, the events being a heavy smoker and having emphysema are not independent.