Basicity of oxides decreases for elements from left to right in the periodic table. The order of increasing basicity is; Cs2O> MgO > SnO2 > P4O10 > Cl2O7.
The oxides of metals are known to be basic. This is a common property of all metals. However, the basicity of metallic oxides decreases across the period. So, from left to right, the oxides of bases become less acidic.
On the other hand, the oxides of nonmetals are acidic in nature. So as we move from left to right, the oxides of metals become more acidic. The order of decreasing basicity of oxides as listed in the question is;
Cs2O> MgO > SnO2 > P4O10 > Cl2O7.
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Answer: First Choice
Explanation:
Like Sancho, Cugoano demonstrates that he had a difficult beginning as an enslaved person, but then prevailed through luck and perseverance.
The value of s that will be able to yield the coordinate (4, 3) is 5.
<h3>How to find the value?</h3>
From the information given, in order to find the value of s, we'll use the Pythagoras theorem. This goes thus:
OA = ✓4² + ✓3²
OA = ✓(16 + 9)
OA = ✓25
OA = 5
Therefore, value of s that will be able to yield the coordinate (4, 3) is 5.
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brainly.com/question/17206319
The number of small cubic blocks that is required to fill the big cubic blocks is 2.
<h3>How to calculate the volume of a cube.</h3>
Mathematically, the volume of a cube is given by the following formula:
Volume of cube = S³
<u>Where:</u>
S is the side length of the cube.
<u>Given the following data:</u>
- Side length of small cube = 1/6 inch.
- Side length of big cube = 2/6 inch.
For the small cube:
Volume of cube = (1/6)³ = 0.5 in³
For the big cube:
Volume of cube = (2/6)³ = 1 in³
Therefore, the number of small cubic blocks that is required to fill the big cubic blocks is given by:
Number = 1/0.5
Number = 2 cubic blocks.
Read more on volume of a cube here: brainly.com/question/25248189
<u>Complete Question:</u>
How many cubic blocks of side length 1/6 inch would it take to fill a cube with a side length of 2/6 inch
