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4 years ago

What percent of 60 is 12? Round to the whole number.

Mathematics

2 answers:

jarptica [38.1K]4 years ago

8 0

The answer to your question is 5

dem82 [27]4 years ago

6 0

Percent formula : is/of = %/100

is = 12
of = 60
% = x

now we sub
12/60 = x/100
this is a proportion, so we cross multiply
(60)(x) = (12)(100)
60x = 1200
x = 1200/60
x = 20

so 20% of 60 = 12

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Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

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3 years ago

Find the cardinal number of the given set.<br><br><br> A = {{3, 5, 7, ... 25}}

Allisa [31]

Answer:

Step-by-step explanation:

The cardinal number of a set is the number of element in the set. Given the set A = {{3, 5, 7, ... 25}}, you can see that the elements of the set are odd numbers from 3 to 25. Writing out the full set;

A = {{3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25}}

Counting the total number of element in the set, you will see that there are only 12 elements in the set. Hence the cardinal number of the set is 12 i.e n(A) = 12

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3 years ago

Jasmine was shopping at a go wet store and saw the following list of prices. She brought $20 to spend on groceries. If she buys

Nookie1986 [14]

4 boxes of cereal: $9

2 liters of soda: $4.20

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3 years ago

Read 2 more answers

What relations are functions

Inessa05 [86]

The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.

A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.

So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.

But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.

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4 years ago

In the park, Bryce hikes 4 1/2 mi and Jessie hikes 6 7/16 mi. How much farther does Jessie hike than Bryce? Express your answer

soldier1979 [14.2K]

is simply the difference of both amounts, but firstly let's convert the mixed fractions to improper, and subtract.

$\bf \stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}}
\\\\\\
\stackrel{mixed}{6\frac{7}{16}}\implies \cfrac{6\cdot 16+7}{16}\implies \stackrel{improper}{\cfrac{103}{16}}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\stackrel{Jessie}{\cfrac{103}{16}}-\stackrel{Bryce}{\cfrac{9}{2}}\implies \stackrel{\textit{our LCD is 16}}{\cfrac{(1)103-(8)9}{16}}\implies \cfrac{103-72}{16}\implies \cfrac{31}{16}\implies 1\frac{15}{16}$

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4 years ago

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