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3 years ago

Find the cardinal number of the given set. A = {{3, 5, 7, ... 25}}

Mathematics

1 answer:

Allisa [31]3 years ago

7 0

Answer:

Step-by-step explanation:

The cardinal number of a set is the number of element in the set. Given the set A = {{3, 5, 7, ... 25}}, you can see that the elements of the set are odd numbers from 3 to 25. Writing out the full set;

A = {{3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25}}

Counting the total number of element in the set, you will see that there are only 12 elements in the set. Hence the cardinal number of the set is 12 i.e n(A) = 12

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In the figure above, solve for x and y.

Naddik [55]

Answer:

x = 34°

y = 15

Step-by-step explanation:

x + 146 = 180

x = 34°

4y + 8 + 5y + 3 + 34 = 180

9y + 45 = 180

y = 15

5 0

2 years ago

subset to real numbers, and as you can see are not at all connected to the rest of numbers (and integers).

Natali5045456 [20]

Irrational numbers are the subset of real numbers that are not at all connected to the rest of numbers.

The subsets of real numbers are natural numbers, whole numbers, integers, rational numbers and irrational numbers.

Natural numbers are subset of whole numbers, which are subset of integers, which are subset of rational numbers. Hence, all of them are interconnected. The set of irrational numbers is the only subset of real numbers which is not associated with the rest.

For example:-

1 is a natural number, whole number, integer, rational number but not irrational number. On the other hand, $\sqrt{2}$ is an irrational number but none of the rest.

To learn more about real numbers, here:-

brainly.com/question/551408

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6 0

2 years ago

The caplan family was going to New York City to ring in the New Year. 16 family members each paid $341 for their plane ticket to

Usimov [2.4K]

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3 0

3 years ago

Let R1 and R2 are the remainders when the polynomials x^3 + 2x^2 − 5ax − 7 and x^3 + ax^2 − 12x + 6 are divided by x + 1 and x −

Andru [333]

Answer:

2.44

Step-by-step explanation:

Given: x³ + 2x² - 5ax - 7 and x³ + ax² - 12x + 6

Also, R1 + R2 = 6

in order to find the value of a:

Let p(x) = x³ + 2x² - 5ax - 7 and q(x) = x³ + ax² - 12x + 6

Using remainder theorem i.e if a polynomial p(x) is divisible by polynomial of form x - a then remainder is given by p(a).

Then,

R1 = p( -1 ) = (-1)³ + 2(-1)² - 5a(-1) - 7 = -1 + 2 + 5a - 7 = 5a - 6

R2 = q( 2 ) = 2³ + a(2)² - 12(2) + 6 = 8 + 4a - 24 + 6 = 4a - 10

Now,

R1 + R2 = 6

5a - 6 + 4a - 10 = 6

9a = 22

a=2.44

Therefore, Value of a is 2.44

7 0

3 years ago

Answer this question please and thank you

Murljashka [212]

Answer:

Step-by-step explanation:

here´s and example for 1

1⁵

1x1x1x1x1=1

so 1 raised to the power of any number is 1

1 multiply by itself any number of times is 1

here´s an example for 0

0⁴

0x0x0x0=0

hence, the vale of 0 raised to any power is 0.

0 multiplied by itself any number of times is 0

8 0

3 years ago