Answer:
(A)
Length of DE = √17
EF = √18
DF = √17
(B) Slope of DE = 4
EF = 1
DF = 1/4
(C) Isosceles triangle.
Step-by-step explanation:
See attached image.
Answer:
y = 40 / x^1/3
Step-by-step explanation:
Given that :
y α x^1/3
y = k * 1 / x^1/3
y = k / x^1/3
When x = 125 ; y = 8
8 = k / 125^1/3
Cube root of 125 = 5
8 = k / 5
8 * 5 = k ; k = 40
Hence, expression becomes :
y = 40 / x^1/3
The height of the tank must be at least 1 foot, or 12 inches. We know the floor area (which is length x width) must be at least 400 inches. Therefore these minimum dimensions already tell us that the minimum volume is 400 x 12 = 4800 cubic inches. Since we have a maximum of 5000 cubic inches, the volume must be within the range of 4800 - 5000 cubic inches.
We can set the height at exactly 1 ft (or 12 inches). Then we can select length and width that multiply to 400 square inches, for example, L = 40 inches and W = 10 in. This gives us a tank of dimensions 40 x 10 x 12 = 4800 cubic inches, which fits all the criteria.
Answer:
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Step-by-step explanation:
