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Ymorist [56]
3 years ago
10

Timing can be a major factor in the success of a business incorporation and emerging technology. Describe one potential problem

associated with an organization purchasing new technology early in its lifecycle. Describe a potential problem associated with an organization waiting too long to purchase a new technology.
Computers and Technology
2 answers:
Brums [2.3K]3 years ago
7 0

Answer:

When a new technology has recently been launched, it tends to be very expensive. For example, cell phones 30 years ago were extremely expensive and using them was also very expensive. You paid your service a certain amount for calls you made and another amount for calls that you received. Also the phones themselves were also very large, heavy and expensive.

On the other hand, if an organization waits too long to adopt new technologies, it might be too late. Sears, JC Penny, Macy's, etc. used to be huge and were an essential part of almost everyone in America. Then Amazon came and instead of adopting internet sales, they insisted on their traditional sales structures. For example, Sears and Kmart currently have only 182 stores open, 15 years ago they had 3,500 stores open.

Serga [27]3 years ago
5 0
The price could go up, it might not work then later down the road
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What is sum after the following loop terminates? int sum = 0; int item = 0; do { item ; sum = item; if (sum > 4) break; } whi
irinina [24]
Int sum = 0;
int item = 0;
do
{
    item;
    sum = item;
    if (sum > 4)
        break;
} while (item < 5);


You will generate a compile error, as having (item;) as a statement on its own is invalid.
8 0
3 years ago
Read 2 more answers
The java class library interface queue method tagg retrieves the entey at the front of a queue but themrows a NosuchElementExcep
SCORPION-xisa [38]

Answer:D) peek

Explanation:Peek operation or function is the method that is used for the returning of the values on the front of the queue or stack type datatypes.               This operation function over those datatypes having group or collection of the elements and does not eliminate any element from the queue.

NOsuchElemnet exception is shown when there is the peek operation in the queue for the element to be displayed on the top and no deletion can take place .Thus, the correct option is option(D).

5 0
3 years ago
There is a population of owls in a forest. In one year there are 20 new owls born and 10 owls die. In this same year, 5 owls ent
Simora [160]

Answer:

The owls population increased by 13 in one year

Explanation:

The given data on the owl population are as follows;

The number of new owls born = 20 (positive increase in population)

The number of owls that die = 10 (negative decrease in population)

The number of owls that enter the forest = 5 (positive increase in population)

The number of owls that left the forest = 2 (negative decrease in population)

Let 'w' represent the number of new owls born, let 'x' represent the number of  owls that die, let 'y' represent the number of owls that enter the forest and let 'z' represent the number of owls that left the forest, we get;

The change in population, ΔP = w - x + y - z

By plugging in the values, we get;

ΔP = 20 - 10 + 5 - 2 = 13

The change in the population of owls in one year is an increase in 13 owls.

4 0
3 years ago
Katla is a project manager. One of the programmers on her team comes to her and says that he permanently deleted some code mista
Aleonysh [2.5K]

Answer:

Version Control - Maintains the code log history and changes overtime.

8 0
3 years ago
Will give brainliest and good amount of points, no false answers.
nlexa [21]

The problem with the swap function is that it loses the value at the first index, as soon as it gets overwritten by the value at the second index. This happens in the first statement. To fix it, you need a helper variable.

First you're going to "park" the index at the first index in that helper variable, then you can safely overwrite it with the value at the second index. Then finally you can write the parked value to the second index:

var swap = function(array, firstIndex, secondIndex) {

let helper = array[firstIndex];

array[firstIndex]  = array[secondIndex];

array[secondIndex] = helper;

};

I hope this makes sense to you.

7 0
3 years ago
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