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Ymorist [56]
2 years ago
10

Timing can be a major factor in the success of a business incorporation and emerging technology. Describe one potential problem

associated with an organization purchasing new technology early in its lifecycle. Describe a potential problem associated with an organization waiting too long to purchase a new technology.
Computers and Technology
2 answers:
Brums [2.3K]2 years ago
7 0

Answer:

When a new technology has recently been launched, it tends to be very expensive. For example, cell phones 30 years ago were extremely expensive and using them was also very expensive. You paid your service a certain amount for calls you made and another amount for calls that you received. Also the phones themselves were also very large, heavy and expensive.

On the other hand, if an organization waits too long to adopt new technologies, it might be too late. Sears, JC Penny, Macy's, etc. used to be huge and were an essential part of almost everyone in America. Then Amazon came and instead of adopting internet sales, they insisted on their traditional sales structures. For example, Sears and Kmart currently have only 182 stores open, 15 years ago they had 3,500 stores open.

Serga [27]2 years ago
5 0
The price could go up, it might not work then later down the road
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. List 5 types of exploits from cybercrime and provide brief definition. (2.5 Marks)
Flura [38]

In cyber security, an exploit is a way attackers take advantage of certain vulnerabilities and gain malicious access to systems. There are very many types of exploits that exist in the cyber security world. However, I will mention those ones most commonly used.

DoS attacks – The denial of service attacks is very common. Hackers will gain access to servers and send so many packet requests at the same time. The servers become overwhelmed due to too much memory allocation and the huge amount of traffic ends up crashing the servers.

Unauthorized access – When an attacker has an illegal access to host machines

<u>Application Exploitation</u>

Code injection – This exploit can be used to maliciously inject invalid code into an application program or software and as a result change how the program behaves.

Cross-site scripting – Enable hackers inject malicious scripts on a website of a client. Once they have gained access, they will escalate their privileges and have more access to the site.

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6 0
3 years ago
How can I use HTML to express a personal value
Mama L [17]

Answer: Order list

Explanation:

7 0
2 years ago
In PKI, the CA periodically distributes a(n) _________ to all users that identifies all revoked certificates.
Trava [24]

Answer:

" CRL (certificate revocation list)" is the appropriate answer.

Explanation:

  • A collection of such subscriber bases containing accreditation or certification status combined with the validation, revocation, or outdated certification within each final customer is known as CRL.
  • Only certain subscribing workstations with a certain underlying cause authentication system should have been duplicated.
4 0
3 years ago
Finish and test the following two functions append and merge in the skeleton file:
avanturin [10]

Answer:

Explanation:

#include <iostream>

using namespace std;

int* append(int*,int,int*,int);

int* merge(int*,int,int*,int);

void print(int*,int);

int main()

{ int a[] = {11,33,55,77,99};

int b[] = {22,44,66,88};

print(a,5);

print(b,4);

int* c = append(a,5,b,4); // c points to the appended array=

print(c,9);

int* d = merge(a,5,b,4);

print(d,9);

}

void print(int* a, int n)

{ cout << "{" << a[0];

for (int i=1; i<n; i++)

cout << "," << a[i];

cout << "}\n";

}

int* append(int* a, int m, int* b, int n)

{

int * p= (int *)malloc(sizeof(int)*(m+n));

int i,index=0;

for(i=0;i<m;i++)

p[index++]=a[i];

for(i=0;i<n;i++)

p[index++]=b[i];

return p;

}

int* merge(int* a, int m, int* b, int n)

{

int i, j, k;

j = k = 0;

int *mergeRes = (int *)malloc(sizeof(int)*(m+n));

for (i = 0; i < m + n;) {

if (j < m && k < n) {

if (a[j] < b[k]) {

mergeRes[i] = a[j];

j++;

}

else {

mergeRes[i] = b[k];

k++;

}

i++;

}

// copying remaining elements from the b

else if (j == m) {

for (; i < m + n;) {

mergeRes[i] = b[k];

k++;

i++;

}

}

// copying remaining elements from the a

else {

for (; i < m + n;) {

mergeRes[i] = a[j];

j++;

i++;

}

}

}

return mergeRes;

}

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3 years ago
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