The simplified expression of (x^0 y^2/3 z^-2y^)^2/3 divided by (x^2 z^1/2)^-6 is x^(12) y^(10/9) z^(-1/3)
<h3>How to simplify the expression?</h3>
The algebraic statement is given as:
(x^0 y^2/3 z^-2y^)^2/3 divided by (x^2 z^1/2)^-6
Rewrite the algebraic statement as:
[(x^0 y^2/3 z^-2y)^2/3]/[(x^2 z^1/2)^-6]
Evaluate the like factors
[(x^0 y^(2/3+1) z^-2)^2/3]/[(x^2 z^1/2)^-6]
Evaluate the sum
[(x^0 y^5/3 z^-2)^2/3]/[(x^2 z^1/2)^-6]
Expand the exponents
[(x^(0*2/3) y^(5/3 * 2/3)z^(-2*2/3)]/[(x^(2*-6) z^(1/2*-6)]
Evaluate the products
[(x^0 y^(10/9) z^(-4/3)]/[(x^(-12) z^(-3)]
Apply the quotient law of indices
x^(0+12) y^(10/9) z^(-4/3+3)
Evaluate the sum of exponents
x^(12) y^(10/9) z^(-1/3)
Hence, the simplified expression of (x^0 y^2/3 z^-2y^)^2/3 divided by (x^2 z^1/2)^-6 is x^(12) y^(10/9) z^(-1/3)
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Answer:
Step-by-step explanation:
this will take awhile so imma help u still okay
Answer:
(4) 1/4x = 3/4 (4)
1x=3
Step-by-step explanation:
3/4 x
÷ = ÷
1/4 1
(4) 1/4x = 3/4 (4)
1x=3
Answer:
is the the equation of parabola that has vertex (9,7) and passes through point (3,8).
Step-by-step explanation:
To solve this you need to use the vertex form of the equation of a parabola which is
Where (h, k) are the coordinates of the vertex.
So, h = 9 and k =7
And one set of points on the graph
x = 3, y = 8
Solving the formula for 
.
To create a general formula for the parabola you would put in the values for a, h, and k and then simplify.
Therefore, is the the equation of parabola that has vertex (9,7) and passes through point (3,8).
The graph is also attached.
Keywords: equation of parabola, vertex, graph
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