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nadezda [96]
3 years ago
5

Miguel ordered a rectangular print for his bedroom. The print is 78 ft wide and 135 ft long

Mathematics
1 answer:
pochemuha3 years ago
8 0
So what's the question
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the value of the 6 in 3.264 is (blank) the value of the 6 in 0.576. a. 10 times as much as or b. 1/10 of
fgiga [73]

The correct answer is ten times as much.

When we look at decimals, each place closer to the decimal point is ten times greater. The first 6 is in the hundreths place and the second one is one spot further away. As a result, the first is 10 times as much as the second.

6 0
3 years ago
The tip of the second hand travels around the edge of the face of a clock. How far does the tip of the second hand travel
Komok [63]

Answer:A. 3 inches

Step-by-step explanation: :)

7 0
2 years ago
Read 2 more answers
Please help me with this and please give me the right answer it’s due tommorow
NARA [144]
First, look and compare at the decimal places in brackets ( ) .

A. (0).561 , (8).627 , (5).325 (wrong)

B. 4.(0)57, 4.(1)22, (5).008 (4.0.., 4.1.., 5.00..) least to greatest - (correct)

C. 1.(7)42 , 1.(5)58, 1.(6)71 - (wrong)

D. Greatest to least - (wrong)
5 0
3 years ago
A 20 meter ladder rests vertically against the side of a barn. A pig that has been hitched to the ladder starts to pull the base
kirill115 [55]

Answer:

I hope my drawing explains well lol... h = 16

Step-by-step explanation:

So basically first you need to find x (the one in the drawing), by doing so, you just have to use the formula,

speed =  \frac{distance}{time}

You substitute in the speed and the time given,

0.4 =  \frac{x}{30}  \\ x = 12

Then, you use the Pythagorean theorem,

h =  \sqrt{ {20}^{2}  -  {12}^{2} } \\  h = 16

7 0
2 years ago
A cylindrical container of four rubber balls has a height of 20 centimeters and a diameter of 5 centimeters. Each ball in the co
Murljashka [212]
The amount of space not occupied by the rubber balls is given by:
Volume=(volume of the container)-(volume of the rubber balls)
volume of the container is given by:
V=πr²h
V=π*(5/2)²(20)
V=392.70 cm³

Volume of each ball is:
V=4/3πr³
V=4/3π(2.5)³=65.45 cm³
volume of four balls
65.45×4=261.8 cm³

The volume of the container that is not occupied by the balls will be:
V=392.70-261.8
V=130.9 cm³
8 0
3 years ago
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