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4 years ago

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A certain type of bacteria increases continuously at a rate proportional to the number present. if there are 500 present at a gi

ven time and 1,000 present 2 hours later, how many hours (from the initial given time) will it take for the numbers to be 2,500

1 answer:

Dima020 [189]4 years ago

6 0

It will take 4 hours, this is because it said it adds 1000 after two hours, and it will add another 1000 two hours later which will give you your answer of four hours

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Find an equation of combined variation where a varies directly as b and inversely as c. One set of values is a = 4, b = 12, and

Ber [7]

Answer:

Combined equation is $a = \frac{kb}{c}$

Step-by-step explanation:

a varies directly as b and inversely as c.

This can be written as

a = $k \times b$

a = kb

where k is the proportionality constant

$a = \frac{kb}{c}$ -------------------------------------(1)

Now lets find the k value bu substituting the given a, b,c values

$4 = \frac{k (12)}{9}$

$9 \times 4 = 12k$

36 = 12 k

$k = \frac{36}{12}$

k = 3

Thus the eq(1) becomes

$a = \frac{3b}{c}$

Let us now find the value of a when b=7 and c = 3

$a = \frac{3(7)}{3}$

$a =\frac{21}{7}$

a = 7

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4 years ago

If IK and LN are parallel lines and M

Dmitrij [34]

Answer:

40°

Step-by-step explanation:

Both angles are opposites so together they equal 180.

180 - 140 = 40

I hope this helps!!

6 0

3 years ago

What is an expression where the solution is 4

Sergeeva-Olga [200]

2+2
<span> ↑
</span>That is an expression. Make sure you don't put the "=" sign since it would become an EQUATION if you did.

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3 years ago

Read 2 more answers

create a word problem that uses division. draw a model to help you write an equation to solve the problem

mixas84 [53]

Try this:
Jonny has 50 apples. He has 5 bags. How many apple does Jonny puts in each abg?

5 0

3 years ago

. The time required for a technician to machine a specific component is normally distributed with a mean of 2 hours and a standa

erma4kov [3.2K]

Answer:

a) There is a 3.84% probability that the technician can machine one component in 1.5 hours or less.

b) There is a 0.42% probability that the technician will require at least 2.75 hours to complete one component

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X.

In this problem, we have to be careful. The mean is in hours, while the standard deviation is in minutes. I am going to work with both in hours, as the problem states. 17 minutes is 0.283 hours, so:

$\mu = 2, \sigma = 0.283$

(a.) What is the probability that the technician can machine one component in 1.5 hours or less?

This probability is the pvalue of the Zscore when $X = 1.5$ . So:

$Z = \frac{1.5 - 2}{0.283}$

$Z = \frac{-0.5}{0.283}$

$Z = -1.77$

$Z = -1.77$ has a pvalue of 0.0384.

This means that there is a 3.84% probability that the technician can machine one component in 1.5 hours or less.

(b.) What is the probability that the technician will require at least 2.75 hours to complete one component?

The pvalue of the score of $X = 2.75$ is the probability that the technican will require less than 2.75 hours to complete one component. The probability that he will require at least 2.75 hours to complete one component is 1 subtracted by this pvalue. So:

$Z = \frac{2.75 - 2}{0.283}$

$Z = \frac{0.75}{0.283}$

$Z = 2.65$

$Z = 2.65$ has a pvalue of 0.99598.

This means that the probability that the technican will require at least 2.75 hours to complete one component is 1 - 0.99598 = 0.0042 = 0.42%.

4 0

4 years ago