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Alchen [17]
4 years ago
10

Solve each equation by completing the square 6) m² + 16m – 8 = 0

Mathematics
1 answer:
Natali5045456 [20]4 years ago
3 0

Answer:

m = - 8 ± 6\sqrt{2}

Step-by-step explanation:

Given

m² + 16m - 8 = 0 ( add 8 to both sides )

m² + 16m = 8

To complete the square

add ( half the coefficient of the m- term )² to both sides

m² + 2(8)m + 64 = 8 + 64

(m + 8)² = 72 ( take the square root of both sides )

m + 8 = ± \sqrt{72} = ± \sqrt{36(2)} = ± 6\sqrt{2}

Subtract 8 from both sides

m = - 8 ± 6\sqrt{2}

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(1+y) (4y+6) =0 algebra 2
marta [7]
Here is your answer! Hope this helped

5 0
3 years ago
Is −4[3(x−7)] and 6(14−2x) equiviant
Paraphin [41]

Answer:

Yes.

Step-by-step explanation:

Set the equations equal to each other to determine their equality.

-4[3(x - 7)] = 6(14 - 2x)

Distribute the 3 and the 6 into their respective parenthesis.

-4[3x - 21] = 84 - 12x

Distribute the -4 into the brackets.

-12x + 84

Rearrange the equations.

84 - 12x = 84 - 12x

Since the equations come out to be the same thing on both sides so that any value satisfies it, the equations are equivalent.

4 0
3 years ago
Solve For X<br> (see picture below) <br><br> thank you!
Mashutka [201]

Answer:

x = 12

Step-by-step explanation:

Given a tangent and a secant from an external point to the circle, then

The square of the tangent is equal to the product of the external part and the entire secant, that is

x² = 6(6 + 18) = 6 × 24 = 144 ( take the square root of both sides )

x = \sqrt{144} = 12

8 0
3 years ago
If the if a cylinder is 7 in tall and has a volume of 63 Pi inches what is the area of the cross section it goes right down the
vitfil [10]

Answer: 9\pi \ in.^2

Step-by-step explanation:

Given

The height of the cylinder is h=7\ in.

The volume of the cylinder is V=63\pi \ in.^3

The volume of the cylinder is the product of area and height

\Rightarrow V=\pi r^2h\\

Insert the values

\Rightarrow 63\pi =A\times 7\\\\\Rightarrow A=\dfrac{63\pi}{7}\\\\\Rightarrow A=9\pi\ in.^2

Thus, the area of the cross-section is 9\pi \ in.^2

7 0
3 years ago
the moon is a sphere with a radius of 567 km. determine an equation for the ellipse if the distance of the satellite from the su
KIM [24]
A=567 km+900 km
a=1,467 km

b=567 km+169 km
b=736 km

x^2/a^2+y^2/b^2=1
x^2/(1,467)^2+y^2/(736)^2=1

Please, see the graph in the attached graph.

Thanks. 

3 0
3 years ago
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