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pantera1 [17]
4 years ago
15

PLEASE HELP ASAP

Mathematics
1 answer:
Tanzania [10]4 years ago
3 0

Answer:

23 nickels / 31 nickels

Step-by-step explanation:

there are 12 quarters in $3 - 12 x 2 is 24. the number of nickels is 1 less than twice the number of quarters. therefore there are 23 nickels. however, there are ten nickels in $1 10 x 3 is 30. and looking at $3.18, one more nickel could fit into the 18 cents. so it would be 31 nickels. the question doesn't make sense. maybe its a trick question?

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Which data set is represented by the modified box plot?
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Answer:A

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For the equation -2(x+1) = 8, Caitlin distributes the 2 to get, -2x +2 = 8. Then she subtracts the 2 from both sides to get -2x
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No.

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She wronged in Step 2, -2x + 2 = 8 .

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Choose the missing step in the given solution to the inequality −2x − 14 &gt; −4 + 3x.
Ne4ueva [31]

Answer:

Step-by-step explanation:

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5 0
3 years ago
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Shoot your shot! When Nick shoots a basketball, he either sinks the shot or misses. For each shot Nick sinks, he is given 5 poin
Misha Larkins [42]

Answer:

Nick sank 8 shots

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- Assume that Nick sinks x shots and misses y shots

- Nick attempts a total of 28 shots

- That means he sinks and misses 28 shots

∴ x + y = 28 ⇒ (1)

- His father give him 5 points (+5) for every sank shot and takes away

 2 points (-2) for every missed shot

- That means his score calculated by adding (<u><em>the number of sank shots</em></u>

<em>   </em><u><em>multiplied by 5</em></u>) and (<u><em>the number of missed shots multiplied by (-2)</em></u>)

- Nick ends up with zero points

∴ 5x + (-2)y = 0

- Remember: (+)(-) = (-)

∴ 5x - 2y = 0 ⇒ (2)

* <em>Now we can solve the two equations by elimination method to find</em>

<em>  the number of sank shots</em>

- Multiply equation (1) by 2 to eliminate y

∴ 2x + 2y = 56 ⇒ (3)

- Add equations (2) and (3)

∴ 7x = 56

- Divide both sides by 7

∴ x = 8

∵ x represents the number of sank shots

∴ Nick sank 8 shots

8 0
3 years ago
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