An electronics store has two options for liquidating televisions that have not sold.

2 answers:

7 0

Answser: first option 350(0.95)^x + 30x - 350

Explanation:

You can figure out the function that shows the difference in price between option 1 and option 2 if you make a table simulating the behavior for a few months:

month price as per option 1 price as per option 2

start 350 350

1 350 - 5% (350) = 350 - 30
 = 350 (0,95)

2 350 (0,95)×(0,95) =
 350 (0,95)² 350 - 30(2)

3 350 (0,95)³ 350 - 30(3)

So now you can figure out the price with each option after x months:

 350 (0.95)ˣ 350 - 30x

And the difference is 350 (0.95)ˣ - [350 - 30x]

Which, expanding the square brackets, is 350 (0.95)ˣ + 30x - 350 ↔ the first option.

DIA [1.3K]3 years ago

3 0

Answer:

Step-by-step explanation:

Answser: first option 350(0.95)^x + 30x - 350

Explanation:

You can figure out the function that shows the difference in price between option 1 and option 2 if you make a table simulating the behavior for a few months:

month price as per option 1 price as per option 2

start 350 350

1 � 350 - 5% (350) = 350 - 30

= 350 (0,95)

2 350 (0,95)×(0,95) =

350 (0,95)² 350 - 30(2)

3 350 (0,95)³ 350 - 30(3)

So now you can figure out the price with each option after x months:

350 (0.95)ˣ 350 - 30x

And the difference is 350 (0.95)ˣ - [350 - 30x]

Which, expanding the square brackets, is 350 (0.95)ˣ + 30x - 350 ↔ the first option.

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