All categories

3 years ago

Which statement is true about the y- intercept of a quadratic function

Mathematics

2 answers:

liraira [26]3 years ago

7 0

Answer:

A. a quadratic function can only have one y-intercep

Crazy boy [7]3 years ago

5 0

Which statement is true about the y- intercept of a quadratic function

a. a quadratic function can only have one y - intercept

You might be interested in

Which equation can be solved by using this expression?

Marat540 [252]

<u>Answer:</u>

The correct answer option is B. 2 = 3x + 10x^2

<u>Step-by-step explanation:</u>

We are to determine whether which of the given equations in the answer options can be solved using the following expression:

$x=\frac{-3 \pm\sqrt{(3)^2+4(10)(2)} }{2(10)}$

Here, $a = 10, b = 3$ and $c=-2$ .

These requirements are fulfilled by the equation 4 which is:

$12=3x+10x^2$

Rearranging it to get:

$10x^2+3x-2=0$

Substituting these values of $a,b,c$ in the quadratic formula:

$x= \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

$x= \frac{-3 \pm\sqrt{(3)^2-4(10)(-2)} }{y}$

3 0

3 years ago

4a - 5 + 2a + 9 = 28

BaLLatris [955]

Answer:a=4

Step-by-step explanation:

Simplifying

4a + -5 + 2a + 9 = 28

Reorder the terms:

-5 + 9 + 4a + 2a = 28

Combine like terms: -5 + 9 = 4

4 + 4a + 2a = 28

Combine like terms: 4a + 2a = 6a

4 + 6a = 28

Solving

4 + 6a = 28

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-4' to each side of the equation.

4 + -4 + 6a = 28 + -4

Combine like terms: 4 + -4 = 0

0 + 6a = 28 + -4

6a = 28 + -4

Combine like terms: 28 + -4 = 24

6a = 24

Divide each side by '6'.

a = 4

Simplifying

a = 4

8 0

4 years ago

Read 2 more answers

What is the answer, and how do I solve that equation in order to get my answer? I really want to get the hang of this.

Mrrafil [7]

Answer:

-x^2+4x+6

Step-by-step explanation:

f(x) = 4x+1

g(x) = x^2 - 5

(f-g) (x) = 4x+1 - ( x^2 - 5)

Distribute the minus sign

= 4x+1 - x^2 +5

Combine like terms

= -x^2+4x+6

6 0

3 years ago

Let f(x) = x^2 + 6x.

rusak2 [61]

Answer:

(A) The slope of secant line is 18.

(B) The slope of secant line is h+16.

Step-by-step explanation:

(A)

The given function is

$f(x)=x^2+6x$

At x=3,

$f(3)=(3)^2+6(3)=27$

At x=9,

$f(9)=(9)^2+6(9)=135$

The secant line joining (3,27) and (9,135). So, the slope of secant line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{135-27}{9-3}=18$

The slope of secant line is 18.

(B)

The given function is

$f(x)=x^2+6x$

At x=5,

$f(5)=(5)^2+6(5)=55$

At x=5+h,

$f(5+h)=(5+h)^2+6(5+h)=h^2 + 16 h + 55$

The secant line joining (5,55) and $(5+h,h^2 + 16 h + 55)$ . So, the slope of secant line is

$m=\dfrac{h^2 + 16 h + 55-55}{5+h-5}$

$m=\dfrac{h^2 + 16 h }{h}$

$m=h+16$

The slope of secant line is h+16.

4 0

4 years ago

Which equation represents a line that passes through (2,-1/2) and has a slope of 3?

krok68 [10]

Answer:

the 3rd one

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers