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2 years ago

Which statement is true about the y- intercept of a quadratic function

Mathematics

2 answers:

liraira [26]2 years ago

7 0

Answer:

A. a quadratic function can only have one y-intercep

Crazy boy [7]2 years ago

5 0

Which statement is true about the y- intercept of a quadratic function

a. a quadratic function can only have one y - intercept

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Jack broke apart 5x216 as (5x200) + (5x16) to multiply mentally.What strategy did Jack use?

777dan777 [17]

D. The distributive property That is what jack used

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3 years ago

2X+15= -3x how do you work this equation

Sphinxa [80]

Answer: $x=-3$

Add 3x to both sides

$2x+15+3x=-3x+3x\\5x+15=0$

Subtract 15 from both sides

$5x+15-15=0-15\\5x=-15$

Divide both sides by 5

$5x/5=-15/5\\x=-3$

8 0

3 years ago

Read 2 more answers

3) solve for x. −1/2(x 2) 11/2 x=3

Travka [436]

-1/2(x + 2) + 11/2 + x = 3
-1/2x - 1 + 11/2 + x = 3
1/2x + 9/2 = 3
1/2x = 3 - 9/2 = -3/2
x = -3/2 * 2 = -3
x = -3

3 0

3 years ago

Expanding Logarithmic Expressions In Exercise, use the properties of logarithms to rewrite the expression as the sum, difference

kicyunya [14]

Answer:

$\\ ln(x^2) - ln(x^2 + 1)$ .

For values of x>0, it can be rewritten as $\\ 2ln(x) - ln(x^2 + 1).$

Step-by-step explanation:

For the expression:

$\\ ln(\frac{x^2}{x^2 + 1})$

We can apply this logarithmical property: $\\ ln(\frac{x}{y}) = ln(x) - ln(y).$

Then,

$\\ \frac{x^2}{x^2 + 1} = ln(x^2) - ln(x^2 + 1).$

If we assume values of x > 0 (non negative values for x), then the expression could be rewritten as follows:

$\\ \frac{x^2}{x^2 + 1} = ln(x^2) - ln(x^2 + 1) = 2 ln(x) - ln(x^2 + 1)$ , since $\\ ln(x^{n}) = n*ln(x).$

We have to remember that domain (all possible values x) for logarithmic function is for all x > 0, or mathematically expressed as:

Domain: $\\ {x | x \in R, x > 0}$

8 0

3 years ago

Round 716,487,250 to the nearest million.

IRINA_888 [86]

7 million because 1 is closer to 7 than to 8

6 0

3 years ago