Question

Does anyone know this? Please help.

Answer 1

Answer:option C is the correct answer

Step-by-step explanation:

The given equation is

6x - 2y = 11

Let us make x the subject of the formula. The first step is to add 2y to both the left hand side and the right hand side of the equation. It becomes

6x - 2y + 2y = 11 + 2y

6x = 11 + 2y

Dividing both the left hand side and the right hand side of the equation by 6. It becomes

6x/6 = (11 + 2y)/6

x = (11 + 2y)/6

We would substitute x = (11 + 2y)/6 into (9^3x)/(9^y). It becomes

[9^3(11 + 2y)/6 ] / (9^y)

= [9^(11 + 2y)/2 ] / (9^y)

= [9^(5.5 + y)/] / (9^y)

We would apply the law of indices

a^b/a^c = a^(b - c)

Therefore

[9^(5.5 + y)/] / (9^y) = 9^(5.5 + y - y)

= 9^(5.5)

= 3^2(5.5)

= 3^11

Answer 2

Answer:

$3^{11}$

Step-by-step explanation:

It is given in the question that:

$6x-2y=11$

Dividing both hand sides by 2, we get:

$3x-y=5.5$

We have to find the value of $\frac{9^{3x} }{9^{y} }$.

From laws of exponents we know:

$\frac{a^{m} }{a^{n}}=a^{m-n}$

So we can write :

$\frac{9^{3x} }{9^{y} }=9^{3x-y}$

                                        $=9^{5.5}=3^{11}$