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mamaluj [8]
3 years ago
13

A rectangular field is 450 meters long and 300 meters wide. What is the area of the field in square kilometers?

Mathematics
1 answer:
rodikova [14]3 years ago
7 0
First you multiply 450 m ×300 m= 135,000 m
Then you convert to Kilometers 135,000 ÷1,000= 135 Kilometers

So the answer is 135 Kilometers
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Suppose Bank One offers a certificate of deposit that pays $5,000 in four years for exchange for $4,000 today. What interest rat
vlada-n [284]

Answer:

Bank One is offering a simple interest rate of 6.25% per annum.

Step-by-step explanation:

Given that Bank One offers a certificate of deposit that pays $ 5,000 in four years for exchange for $ 4,000 today, to determine what interest rate is Bank One offering the following calculation must be performed:

(5000 - 4000) / 4 = X

1000/4 = X

250 = X

4000 = 100

250 = X

250 x 100/4000 = X

25000/4000 = X

6.25 = X

Therefore, Bank One is offering a simple interest rate of 6.25% per annum.

7 0
3 years ago
Find the sum of a finite geometric sequence from n = 1 to n = 8, using the expression −2(3)^n − 1.
Kazeer [188]
The sum if the geometric sequence given by:
an=-2(3)^(n-1)
will be:
when:
n=1
an=-2
when n=2
a2=-6
when n=3
a3=-18

when n=4
a4=-54

when n=5
a5=-162

when n=6
a6=-486

when n=7
a7=-1458

when n=8
a8=-4374

thus the summation of the term will be:
Sn=(-4374+-1458+-486+-162+-54+-18+-6+-2)
Sn=-6560
the answer is -6560

6 0
3 years ago
What is the measure of x? Help me on this Geometry question.​
AlladinOne [14]

Answer:

21°

Step-by-step explanation:

the angles of triangle abc has to = 180 so subtract the known angles to get 21

angles bca and daf have to be the same so its 21

8 0
3 years ago
Read 2 more answers
A standard weight known to weigh 10 grams. Some suspect bias in weights due to manufacturing process. To assess the accuracy of
notsponge [240]

Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.01 = 0.99, so Z = 2.327.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.327\frac{0.0003}{\sqrt{5}} = 0.00031

The lower end of the interval is the sample mean subtracted by M. So it is 10.0044 - 0.00031 = 10.00409 grams

The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

M = z\frac{\sigma}{\sqrt{n}}

0.0001 = 2.327\frac{0.0003}{\sqrt{n}}

0.0001\sqrt{n} = 2.327*0.0003

\sqrt{n} = \frac{2.327*0.0003}{0.0001}

(\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2

n = 48.73

Rounding up

49 measurements are needed.

7 0
3 years ago
BRAINLIEST!PLEASE HELP ME
kkurt [141]

-12x - 0.4 > 0.2(36.5x + 80) - 55    Remove the brackets.

-12x - 0.4 > 7.3x + 16 - 55               Combine the like terms on the right

-12x - 0.4 > 7.3x - 39                      Add 12x to both sides

- 0.4 > 7.3x + 12x - 39    

- 0.4 > 19.3x - 39                            Add 39 to both sides.

-0.4 + 39 > 19.3x                              Combine like terms on the left

38.6 > 19.3x                                    Divide by 19.3

38.6 / 19.3 > x

2 > x

6 0
3 years ago
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