B is incorrect because the absolute value of -1 is 1 the absolute value of anything is always positive sorry if I’m incorrect
Answer:
Step-by-step explanation: and
What’s the question
First, you separate the h variable by subtracting s^2 on both sides of the equation, getting
V - s^2 = sh/2
Then, all you have to do is divide both sides by s/2, so you get
h = 2*(v - s^2)/s as your final answer.
Answer:
option D
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Step-by-step explanation:
An expression is undefined when you get division by zero or in simple words when denominator is zero.
Now we will solve each expression one be one by plugging value of x = 0
<h3>1)</h3><h3>

</h3>

-4/-3 = 4/3
<h3>2)</h3><h3>

</h3>

0/-3 = 0
<h3>3)</h3>


6/1
6
<h3>4)</h3>
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
<h3>-8/0</h3><h3>undefined</h3>
Pythagorean Theorum since that is what you are trying to prove.