Answer:
scale factor = 5
Step-by-step explanation:
To determine the scale factor calculate the ratio of corresponding sides of the enlargement to the original, that is
scale factor = =
= 5
A delivery truck is transporting boxes of two sizes: large and small. The large boxes weigh 55 pounds each, and the small boxes
weigh 20 pounds each. There are 125 boxes in all
1 answer:
Answer:
The number of large boxes is 55 and the number of small boxes is 70
Step-by-step explanation:
<u><em>The complete question is</em></u>
A delivery truck is transporting boxes of two sizes: large and small. The large boxes weigh 50 pounds each, and the small boxes weigh 20 pounds each. There are 125 boxes in all. If the truck is carrying a total of 4150 pounds in boxes, how many of each type of box is it carrying?
Let
x ------> the number of large boxes
y -----> the number of small boxes
we know that
-----> equation A
----> equation B
Solve the system by graphing
Remember that the solution of the system of equations is the intersection point both graphs
The intersection point is (55,70)
therefore
The number of large boxes is 55 and the number of small boxes is 70
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Answer:
a. The amount Taylor will need to finance is $8,000
b. The amount Taylor pays as interest in one year is $400
Step-by-step explanation:
The given parameters of the financing for the car are;
The cost of the car Taylor plans to purchase, C = $10,000
The amount Taylor has saved to be used as down payment, S = $2,000
The interest rate of the credit Taylor is offered = 5%
The duration given for repayment of the loan = 5 years
a. To purchase the car, the amount Taylor will need to finance, 'P', is given as follows;
P = C - S
∴ P = $10,000 - $2,000 = $8,000
b. The amount of interest on the loan in one year, 'I', is given by the following formula;
Where;
I = The interest payed
P = The principal amount taken as loan = $8,000
R = The interest rate = 5% APR
T = The time period the interest is applied = 1 year
Plugging in the values, we get;
The interest Taylor will pay on the loan in one year, I = $4,00