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3 years ago

Use the graph of the function. Determine Over what interval(s) the function is positive or negative.

Mathematics

1 answer:

san4es73 [151]3 years ago

4 0

Answer:

I can't see the numbers well, but the graph is decreasing from (-inf, minimum) and increasing from (minimum, inf). The minimum is the vertex. Hope this helps!

Step-by-step explanation:

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HELP!! <3 Right now, the gym covers an area of x square feet. Ms.Lauren wants to increase the size of the gym by 20%. Which e

katrin [286]

Answer:

Step-by-step explanation:

0.20x only tells you 20% of the original gym size, not the increased size of the gym.

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3 years ago

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Solve by factoring x^2-8x-20-0

Oksana_A [137]

X^2-8x-20 and if you rewrite that it’s (x-10) (x+2)

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2 years ago

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5x + 5 = x + 45<br><br> PLEASE HELP

Ostrovityanka [42]

$5x+5=x+45$

We'd rather not have x on both sides of the equation when trying to solve this. To eliminate the x on the right side, subtract both sides by x.

$5x+5-x=x+45-x$
$4x+5=45$

Let's get eliminate the "5" on the left side. Subtract both sides by 5.

$4x+5-5=45-5$
$4x=40$

To finish this, divide both sides by 4.

$4x \div 4=40 \div 4$
$x=10$

That is the answer. Hope this helps! :)

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3 years ago

Express the equation in rectangular form<br> a) r = 2sin(2Θ)<br> b) r = 4cos(3Θ)

Dafna11 [192]

Answer:

a. sqrt(x^2+y^2) * (x^2+y^2) = 4xy

b. (x^2+y^2)^2 = 4x{ (x^2 - 3 y^2}

Step-by-step explanation:

a) r = 2sin(2Θ)

r* = 2 sin 2 theta

We know sin 2theta = 2 sin theta cos theta

r = 2 * 2 sin theta cos theta

sin theta = y/r and cos theta = x/r

r = 4 y/r * x/r

r = 4xy / r^2

Multiply each side by r^2

r^3 = 4xy

r * r^2 = 4xy

We know r = sqrt(x^2+y^2) and r^2 = (x^2+y^2)

sqrt(x^2+y^2) * (x^2+y^2) = 4xy

b) r = 4cos(3Θ)

we know that cos 3 theta = cos^3(theta) - 3 sin^2(theta) cos(theta)

r = 4 *cos^3(theta) - 3 sin^2(theta) cos(theta)

Factor out a cos theta

r = 4 *cos(theta){ cos^2 (theta) - 3 sin^2(theta) }

We know that sin theta = y/r and cos theta = x/r

r = 4 (x/r) { (x/r)^2 - 3 (y/r)^2}

r = 4 *(x/r) { (x^2/r^2 - 3 y^2/r^2}

Multiply by r

r^2 = 4x { (x^2/r^2 - 3 y^2/r^2}

Multiply by r^2

r^2 *r^2 = 4x { (x^2 - 3 y^2}

r^4 = 4x{ (x^2 - 3 y^2}

We know r^2 = (x^2+y^2)

(x^2+y^2)^2 = 4x{ (x^2 - 3 y^2}

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3 years ago

Hurrrryyyyyy I neeedddd helppppp please

ycow [4]

Answer:

y= 1/2 X + 3/4

Step-by-step explanation:

..........

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3 years ago