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9.99x10 ^-2 + 1.11 × 10^-2 i dont have the same scientific calculator as the one from school. Would like to verify my math is co
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pls dont kill me for wacky lines. this shall just give you a basic idea. the important part is the 90° angle
Given:
The figure of a rhombus QRST.
To find:
A. The value of x.
B. The measure of angle RQP.
Solution:
A. We need to find the value of x.
We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.
[Right angle]
Divide both sides by 5.
Therefore, the value of x is 15.
B. We need to find the measure of angle RQP.
From the given figure, it is clear that
Putting , we get
Therefore, the measure of angle RQP is 33 degrees.