2 years ago

To the person who makes a graph and doesn't copy from another question

1 answer:

7 0

Answer:

H=9;8)

B=(5;4) (ball)

R=(7;0) (hit point)

B'=symetric of B axis perpendicular of x in R

B'=(7+(7-5);4)=(9;4)

Equation BR: y-4=(0-4)/(7-5)(x-5)==>y=-2x+14

Equation RB': y-4=(4-0)/(9-7)(x-9)==>y=2x-14

Is H a point of RB'? y=2x-14 : 8=? 2*9-14==>8=?4 No!

you will not make your putt

Step-by-step explanation:

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