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Svetach [21]
3 years ago
5

Caitlin had 402. In her bank account.she withdrew $15.each week to pay for swimming lesson. She now has $237.

Mathematics
1 answer:
Ne4ueva [31]3 years ago
3 0

Amount of money that Caitlin in her account = $ 402

In each week , she withdrew $ 15.

Let number of weeks she had paid money for Swimming lesson = $ 237

Writing the above statement in equation form

⇒ 402 - 15 n = 237

⇒ 402 - 237 = 15 n

⇒ 15 n = 165

Dividing both side by 15, we get

n= 11

→Number of weeks that Caitlin had learnt Swimming = 11 Weeks

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Which values of c will cause the quadratic equation –x2 3x c = 0 to have no real number solutions? check all that apply.
nika2105 [10]

The given quadratic equation will not have any real solution for c<-9/4.

The given quadratic equation is:

-x^{2} +3x+c=0

<h3>What is a quadratic equation?</h3>

Any equation of the form ax^{2} +bx+c=0 is called a quadratic equation with a≠0.

In order to have no real solution, the discriminant of a quadratic equation will be less than zero.

D < 0

3^{2} -4(-1)(c) < 0

9+4c < 0

c < -\frac{9}{4}

For c < -\frac{9}{4} the given quadratic equation will have no real solutions.

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To get more about quadratic equations visit:

brainly.com/question/1214333

5 0
2 years ago
Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall f
spin [16.1K]

Answer:

Part 1) 0.50 inches

Part 2) 1.14 inches

Part 3)

a) 1.25 inches

b) -0.32 inches

Step-by-step explanation:

The complete question in the attached figure

Part 1) Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall for the last June

Let

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

The difference  between the average rainfall and the actual rainfall for the last June is given by the expression

(x-y)

we have

x=0.67\ in\\y=0.17\ in

substitute

0.67-0.17=0.50\ in

Part 2) The departure from the average rainfall last July was -0.36 inches. How much rain fell last July?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

so

D=y-x

we have

D=-0.36\ in\\x=1.5\ in

substitute the given values

-0.36=y-1.5

solve for y

y=1.5-0.36\\y=1.14\ in

Part 3)

<u>Part a)</u> How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

<u>Part b</u>) What would the departure from the average be in August in that

situation?

Part a) How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

Find the average rainfall for these three months

Adds the average rainfall and divide by 3

(0.67+1.5+1.57)/3=1.25\ in

Part b) What would the departure from the average be in August in that

situation?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

so

D=y-x

we have

x=1.57\ in\\y=1.25\ in

substitute the given values

D=1.25-1.57=-0.32\ in

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Answer:

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Step-by-step explanation:

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