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bonufazy [111]
3 years ago
7

Which equation can pair with 3x + 4y = 8 to create a consistent and independent system? 6x + 8y = 16 –3x – 4y = –6 6x – 3y = 2 –

3x – 4y = –8
Mathematics
2 answers:
pogonyaev3 years ago
7 0

The right answer is C)

Consistent and independent system of two linear equations is a system such that there is only one solution for the system, that is, the two straight lines cross at a point. So we can analyze each case and I have attached some graphs to provided you with examples. Those graphs aren't about the equations but it's about general cases:

A) Consistent and dependent. If we divide this given equation by 2 we get the same line. (See Figure 1)

B) Inconsistent. No solutions. (See Figure 2)

C) Consistent and Independent. (See Figure 3)

D) Consistent and dependent.

OLga [1]3 years ago
7 0

Answer:

c

Step-by-step explanation:

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Ezekiel bought a 18 ounce box of chocolate for $6.50. What was the cost per ounce? in a explanation order
vivado [14]

Answer:0.36

Step-by-step explanation:

You divide 18 by 6.50, that give you the cost per ounce

7 0
3 years ago
140 + (-122) + (-10), I also need it with work.
Aleks04 [339]

Answer:

8

Step-by-step explanation:

140-122=18

18-10=8

6 0
3 years ago
Read 2 more answers
If the length of a leg of a triangle is 39.2 and the area of the triangle is 63 what is the length of the other leg
Nadya [2.5K]

Answer:

The length of the other leg is 3.21\ units

Step-by-step explanation:

I will assume that the triangle is a right triangle

In a right triangle the legs are perpendicular

so

The area of a right triangle is equal to

A=\frac{1}{2}(a)(b)

where

a and b are the legs of the triangle

In this problem we have

a=39.2\ units

A=63\ units^{2}

substitute the values

63=\frac{1}{2}(39.2)(b)

126=(39.2)(b)

b=126/(39.2)=3.21\ units

7 0
3 years ago
gail ran 4<img src="https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B10%7D" id="TexFormula1" title="\frac{6}{10}" alt="\frac{6}{10}" ali
erastovalidia [21]
92/25=3.68 I hope this help
3 0
3 years ago
Two points on L1 and two points on L2 are given. Use the slope formula to determine if lines L1 and L2 are parallel, perpendicul
vlada-n [284]

Answer:

The lines L1 and L2 neither parallel nor perpendicular

Step-by-step explanation:

* Lets revise how to find a slope of a line

- If a line passes through points (x1 , y1) and (x2 , y2), then the slope

 of the line is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- Parallel lines have same slopes

- Perpendicular lines have additive, multiplicative slopes

 ( the product of their slopes is -1)

* Lets solve the problem

∵ L1 passes through the point (1 , 10) and (-1 , 7)

- Let (1 , 10) is (x1 , y1) and (-1 , 7) is (x2 , y2)

∴ x1 = 1 , x2 = -1 and y1 = 10 , y2 = 7

∴ The slope of L1 is m1 = \frac{7-10}{-1-1}=\frac{-3}{-2}=\frac{3}{2}

∵ L2 passes through the point (0 , 3) and (1 , 5)

- Let (0 , 3) is (x1 , y1) and (1 , 5) is (x2 , y2)

∴ x1 = 0 , x2 = 1 and y1 = 3 , y2 = 5

∴ The slope of L2 is m2=\frac{5-3}{1-0}=\frac{2}{1}=2

∵ m1 = 3/2 and m2 = 2

- The two lines have different slopes and their product not equal -1

∴ The lines L1 and L2 neither parallel nor perpendicular

7 0
3 years ago
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